在J2ME中切换可显示时获取nullpointer异常

时间:2010-11-23 14:56:15

标签: forms java-me

所以我在我的J2ME应用程序中添加了一个表单,但在尝试返回主屏幕时总是得到一个nullpointer异常。当我使用画布时,这似乎不会发生,我可以成功返回主菜单。是什么给了什么?

从主midlet启动表单

quickAlarm = new QuickAlarm("Set quick alarm",this);
                display.setCurrent(quickAlarm);

QuickAlarm中的构造函数

public QuickAlarm(String title,HelloMIDlet midlet) {
      super(title);
      df = new DateField("Alarm time",DateField.TIME);
      this.append(df);
      this.midlet = midlet;

      backCommand = new Command("Back",Command.BACK,0);
      saveCommand = new Command("Save",Command.OK,1);

      this.addCommand(backCommand);
      this.addCommand(saveCommand);
    }

从QuickAlarm返回主菜单,

this.midlet.leaveCanvas();

这是在主要的midlet

 public void leaveCanvas() {
      display.setCurrent(startOptions);
 }

完整错误是

TRACE: <at java.lang.NullPointerException:   0>, Exception caught in Display class
java.lang.NullPointerException:   0
        at javax.microedition.lcdui.Display$ChameleonTunnel.callScreenListener(), bci=46
        at com.sun.midp.chameleon.layers.SoftButtonLayer.processCommand(), bci=74
        at com.sun.midp.chameleon.layers.SoftButtonLayer.soft1(), bci=37
        at com.sun.midp.chameleon.layers.SoftButtonLayer.keyInput(), bci=36
        at com.sun.midp.chameleon.CWindow.keyInput(), bci=38
        at javax.microedition.lcdui.Display$DisplayEventConsumerImpl.handleKeyEvent(), bci=17
        at com.sun.midp.lcdui.DisplayEventListener.process(), bci=277
        at com.sun.midp.events.EventQueue.run(), bci=179
        at java.lang.Thread.run(Thread.java:637)

2 个答案:

答案 0 :(得分:0)

无视,我只是忘了设置命令监听器。

答案 1 :(得分:0)

定义什么是“quickAlarm”&amp; “startOptions”。你应该能够在“display.setCurrent()”方法中传递“Displayable”对象。所以检查它是否为“quickAlarm”&amp; “startOptions”它们是“javax.microedition.lcdui.Displayable”的子类