我有一个数据集如下:
Source Rev_Diff Cost_Diff Price_Diff Sales_Diff
A -10 10 11 12
B 11 -10 -10 11
C -12 10 10 -11
D -11 -11 -10 -12
如何在以下位置添加列:
“如果Rev_Diff小于0, 如果“Cost_Diff”的金额小于0,则打印“成本”, 如果“Price_Diff”的金额小于0,则打印“价格”, 如果“Sales_Diff”的金额小于0,则打印“Sales”, 否则打印“我们起来了”。
最终输出:
Source Rev_Diff Cost_Diff Price_Diff Sales_Diff Reason Down
A -10 -10 11 12 Cost (-10)
B 11 -10 -10 11 We're Up
C -12 10 10 -11 Sales (-11)
D -11 -11 -10 -12 Cost (-11), Price (-11), Sales (-12)
答案 0 :(得分:1)
我无法完全了解您希望如何构建if语句,但以下内容可以根据前一列中的信息添加新列。
Source <- c("A", "B", "C", "D", "E")
Rev_Diff <- c(-10, 11, 12, 11, 10)
Cost_Diff <- c(10, -10, 10, -11, 11)
Price_Diff <- c(-11, 10, -10, 10, 10)
Sales_Diff <- c(12, 11, 11, -12, 11)
df <- data.frame(Source, Rev_Diff, Cost_Diff, Price_Diff, Sales_Diff)
df %>%
mutate(ReasonDown = ifelse(Rev_Diff < 0, paste("Rev", Rev_Diff),
ifelse(Cost_Diff < 0, paste("Cost", Cost_Diff),
ifelse(Price_Diff < 0, paste("Price", Price_Diff),
ifelse(Sales_Diff < 0, paste("Sales", Sales_Diff), "We're up")))))
Source Rev_Diff Cost_Diff Price_Diff Sales_Diff ReasonDown
1 A -10 10 -11 12 Rev -10
2 B 11 -10 10 11 Cost -10
3 C 12 10 -10 11 Price -10
4 D 11 -11 10 -12 Cost -11
5 E 10 11 10 11 We're up
但是,ifelse会在找到TRUE语句后停止,因此无法打印出多个&#34; Down原因&#34;就像你在Source D中所做的那样。如果你真的想要打印所有内容,我认为你应该能够添加4个新列来检查每个Rev,Cost,Price,Sales,并添加第5列来总结所有内容。 / p>
df %>%
mutate(RRev = ifelse(Rev_Diff < 0, paste("Rev", Rev_Diff), "")) %>%
mutate(RCost = ifelse(Cost_Diff < 0, paste("Cost", Cost_Diff), "")) %>%
mutate(RPrice = ifelse(Price_Diff < 0, paste("Price", Rev_Diff), "")) %>%
mutate(RSales = ifelse(Sales_Diff < 0, paste("Sales", Rev_Diff), "")) %>%
mutate(DownReason = ifelse(nchar(paste(RRev, RCost, RPrice, RSales)) > 3, paste(RRev, RCost, RPrice, RSales), "We're UP"))
Source Rev_Diff Cost_Diff Price_Diff Sales_Diff RRev RCost RPrice RSales DownReason
1 A -10 10 -11 12 Rev -10 Price -10 Rev -10 Price -10
2 B 11 -10 10 11 Cost -10 Cost -10
3 C 12 10 -10 11 Price 12 Price 12
4 D 11 -11 10 -12 Cost -11 Sales 11 Cost -11 Sales 11
5 E 10 11 10 11 We're UP