即使使用stringsAsFactors = F,也无法阻止R读取.csv文件作为因素吗?

时间:2017-03-02 17:01:00

标签: r

我有一个如下所示的CSV文件:

t.trend.dates.  sig
2/23/2017   2
2/23/2017   4
2/23/2017   6
2/23/2017   8
2/23/2017   9
2/23/2017   11
2/23/2017   12
2/23/2017   13
2/22/2017   14
2/23/2017   15
2/23/2017   16
2/23/2017   17
2/23/2017   18
2/23/2017   19
2/23/2017   20
2/23/2017   21
2/22/2017   24

我已经使用

将其读入R.
TrendIndices <- read.csv("TrendingSignals.csv", header = TRUE, sep=" ")

然后返回

   t.trend.dates. X..sig.
1      2017-02-23      ,2
2      2017-02-23      ,4
3      2017-02-23      ,6
4      2017-02-23      ,8
5      2017-02-23      ,9
6      2017-02-23     ,11
7      2017-02-23     ,12
8      2017-02-23     ,13
9      2017-02-22     ,14
10     2017-02-23     ,15
11     2017-02-23     ,16
12     2017-02-23     ,17
13     2017-02-23     ,18
14     2017-02-23     ,19
15     2017-02-23     ,20
16     2017-02-23     ,21
17     2017-02-22     ,24
> str(TrendIndices)
'data.frame':   17 obs. of  2 variables:
 $ t.trend.dates.: Factor w/ 2 levels "2017-02-22","2017-02-23": 2 2 2 2 2 2 2 2 1 2 ...
 $ X..sig.       : Factor w/ 17 levels ",11",",12",",13",..: 10 14 15 16 17 1 2 3 4 5 ...

我已经尝试过两次

write.csv(sig.trend, file="TrendingSignals", row.names = False, stringsAsFactors=FALSE)
TrendIndices <- read.csv("TrendingSignals.csv", header = TRUE, sep=" ", stringsAsFactors=FALSE)

但我一直收到错误&#34; eval中的错误(expr,envir,enclos):object&#39; False&#39;找不到&#34;

非常感谢帮助。

1 个答案:

答案 0 :(得分:0)

你可以试试这个:

TrendIndices <- read.table("TrendingSignals.csv", sep = "" , header = TRUE
 , stringsAsFactors= FALSE)

给出:

> TrendIndices
   t.trend.dates. sig
1       2/23/2017   2
2       2/23/2017   4
3       2/23/2017   6
4       2/23/2017   8
5       2/23/2017   9
6       2/23/2017  11
7       2/23/2017  12
8       2/23/2017  13
9       2/22/2017  14
10      2/23/2017  15
11      2/23/2017  16
12      2/23/2017  17
13      2/23/2017  18
14      2/23/2017  19
15      2/23/2017  20
16      2/23/2017  21
17      2/22/2017  24
> str(TrendIndices)
'data.frame':   17 obs. of  2 variables:
 $ t.trend.dates.: chr  "2/23/2017" "2/23/2017" "2/23/2017" "2/23/2017" ...
 $ sig           : int  2 4 6 8 9 11 12 13 14 15 ...