Question

我不知道如何用我选择的数字交换数组中的最小数字。我必须使用的方法是swapNum（）。然后在我这样做之后，我必须打印出数组，但是我从swapNum（）做了修改

public class Data
{
    private int numbers[] = {1, 2, 3, 4, 5, 5, 6, 7, 8, 9, 10,};

    private int smallNum = numbers[0];
    private int largeNum = numbers[0];

    private int countNum = 0;

    public void setsmallNum(int smallNum)
    { this.smallNum = smallNum; }

    public void setlargeNum(int largeNum)
    { this.largeNum = largeNum; }

    public void setcountNum(int countNum)
    { this.countNum = countNum; }

    public int getsmallNum()
    {
        for(int i = 0; i < numbers.length; i++)
        {
            if(numbers[i] < smallNum)
            {
            smallNum = numbers[i];
            }
        }
        return smallNum;
    }

    public int getlargeNum()
    {
        for(int i = 0; i < numbers.length; i++)
        {
            if(numbers[i] > largeNum)
            {
                largeNum = numbers[i];
            }
        }
        return largeNum;
    }

    public int getcountNum()
    {
        int counter = 0;
        for(int i = 0; i < numbers.length; i++)
        {
            if(numbers[i] == countNum)
            {
                counter++;
                System.out.println("Number is at index: " + i);
            }
        }
        return counter;
    }

    public int swapNum()
    {
    /* swap lowest number in array with a selected number 
       that I choose such as d.setcountNum(5)
    */
    }

    public static void main(String[] args)
    {
        Data d = new Data();
        d.getlargeNum();
        d.getsmallNum();
        d.setcountNum(5);
        System.out.println("Largest number: " + d.getlargeNum());
        System.out.println("Smallest number: " + d.getsmallNum());
        System.out.println("Number appears " + d.getcountNum() + " times");
     // System.out.println(Print out the modified array from swapNum() method)
    }
}

Answer 1

根据您的代码，最小的数字存储在全局smallNum变量中。

使用此值创建一个函数，您可以选择多个参数作为参数。然后找到数组中的最小数字并使用temp变量进行交换。

public int swapNum(int num){
    int temp = 0;
    for(int i=0; i<numbers.length; i++) 
         if(numbers[i] == smallNum){ //find smallest value in array.
             temp = numbers[i];
             numbers[i] = num;
         }
     }
     return temp; //You can return the value that was swapped
}

创建另一个显示numbers数组内容的函数。随时调用它。

    public void display(){
        for(int i=0; i<numbers.length; i++){
            System.out.print(numbers[i]+" ");
        }
        System.out.println();
    }

可以进行一些修改以提高代码效率。

Java使用所选数字交换数组中的最小数字

1 个答案: