Question

我有几天试图弄清楚如何解决这个问题，但我找不到解决方案。我已经尝试了所有的建议，但我仍然无法弄清楚如何显示最低的数字。

 import java.util.Scanner;


  public class finalname {
  public static void main(String args[]) {
   Scanner kb = new Scanner(System.in);

  System.out.println("How Many Numbers You Want To Enter: ");
  int total = kb.nextInt();
  int input = 0;
  int sum = 0;
  int average=0;
  int max = Integer.MIN_VALUE;
  int min = Integer.MAX_VALUE;
  while (input < total) {
    input++;

    System.out.println("Enter " + input + ". Operand: ");

                sum += kb.nextInt();

    if (min >= sum) 
     { 
         min = sum;
     } 
   if (max <= sum) 
    { 
     max = sum;
     } 



   average = ( sum ) / ( input);
}
System.out.println("The sum is " + sum + ".");
System.out.println("The avg  " + average);
System.out.println("The highest number  " + max);
System.out.println("The the lowest number " + min);


 }
 }

Answer 1

为什么你+= sum？如果您只是想从输入数字中获取最小数字。比改变

 sum += kb.nextInt();

要

  int n=kb.nextInt();
  sum += n;// += will sum your input. It is only need for average.

  if(min>n)// To get smallest number from input

Answer 2

您的代码非常接近工作，但是当您必须比较刚输入的实际数字时，您正在比较sum。

将数字保存到变量：

int num = kb.nextInt();

sum += num;

if (num < min)
    min = num;

if (num > max)
    max = num;

循环后，计算平均值注意：您应该考虑将average设为float，以便显示小数结果：

float average = (float) (sum / input);

在Java中显示最小的数字

2 个答案: