当我尝试在索引操作中显示链接数据时 - 我无法避免使用标准包含的N + 1问题。例如:
Model 1 - Pet (let it will be animal: title:string. Pet can has many PetAttributeElems, they show attributes this Pet have and what values they have)
Model 2 - PetAttribute (this model contains only titles of attributes, like weight, age and 1000+ more attributes. PetAttribute has many PetAttributeElems - one attribute, such as weight, can be described for many Pets)
Model 3 - PetAttributeElem (this model belongs to pet and to petAttribute, also it has value field, that show value of attribute for pet.
当我做show
动作时 - 我在HAML中使用:
-@pet.pet_attribute_elems.includes(:pet_attribute).each do |elem|
="#{elem.pet_attribtute.title}: #{elem.value}"
但是当我做index
动作时,我想使用:
-@pets.each do |pet|
-pet.pet_attribute_elems.includes(:pet_attribute).each do |elem|
="#{elem.pet_attribtute.title}: #{elem.value}"
对于每个includes
pet
方法将调用许多SQL查询
现在我通过手动创建这样的附加对象来解决它:
@pet_elems = {}
PetAtributeElems.includes(:pet_attribute)
.where(pet_id:@pets.map(&:id)).each do |elem|
pet_id = elem.pet_id
if @pet_elems.include?(pet_id)
@pet_elems[pet_id] << elem
else
@pet_elems[pet_id] = [elem]
end
end
我可以使用:
-@pets.each do |pet|
-if @pet_elems.include?(pet.id)
-@pet_elems[pet.id].each do |elem|
="#{elem.pet_attribtute.title}: #{elem.value}"
我怎样才能更轻松地解决这个问题?
答案 0 :(得分:1)
你正沿着非rails-convention路径前进。
将代码移出视图,因此只需
= render @pet_attribute_elems
部分处理显示
# _pet_attribute_elems.html.haml
="#{pet_attribute_elem.pet_attribtute.title}: #{pet_attribute_elem.value}"
在控制器中,执行查询
def show
@pet = Pet.find(...)
@pet_attribute_elems = @pet.pet_attribute_elems.includes(:pet_attribute)
end
def index
@pet_attribute_elems = PetAttributeElem.includes(:pet_attribute)
end