Question

我想要唯一地合并json数据。我有两个json数据，需要一个生成的json数据，它以独特的方式包含两个json数据。

$json1 = '[{"name":"A1","phone":"123"}, {"name":"A2","phone":"456"}]';
$json2 = '[{"name":"A1","phone":"123"}, {"name":"A3","phone":"789"}]';

$decoded_json1 = json_decode($json1, true);
$decoded_json2 = json_decode($json2, true);

var_dump($decoded_json1);
var_dump($decoded_json2);

$merge_json = array_merge($decoded_json1, $decoded_json2);

var_dump($merge_json);

/* I want json data like this
[{"name":"A1","phone":"123"}, {"name":"A2","phone":"456"}, {"name":"A3","phone":"789"}]
 */

但上面的代码不能正常合并json数据，但问题是它不是唯一的这个对象{"name":"A1","phone":"123"}重复。

更新

  $json2 = '[{"name":"A1","phone":"123"}, {"name":"A3","phone":"789"}, {"name":"A1","phone":"000"}]';

Answer 1

PHP并不知道什么是独特的，什么不是，你需要手动执行此操作。

码

<?php

$json1 = '[{"name":"A1","phone":"123"}, {"name":"A2","phone":"456"}]';
$json2 = '[{"name":"A1","phone":"123"}, {"name":"A3","phone":"789"}]';

$decoded_json1 = json_decode($json1, true);
$decoded_json2 = json_decode($json2, true);

$newArray = [];

foreach($decoded_json1 as $row) {
    $hash = hash('SHA256', json_encode($row));
    $newArray[$hash] = $row;
}

foreach($decoded_json2 as $row) {
    $hash = hash('SHA256', json_encode($row));
    $newArray[$hash] = $row;
}

// remove the hash keys
$newArray = array_values($newArray);

var_dump($newArray);

输出

array(3) {
  [0]=>
  array(2) {
    ["name"]=>
    string(2) "A1"
    ["phone"]=>
    string(3) "123"
  }
  [1]=>
  array(2) {
    ["name"]=>
    string(2) "A2"
    ["phone"]=>
    string(3) "456"
  }
  [2]=>
  array(2) {
    ["name"]=>
    string(2) "A3"
    ["phone"]=>
    string(3) "789"
  }
}

Answer 2

array_merge（）仅过滤重复的关键成员，因此您可以使用json_encode()，json_decode()和array_unique()来执行此操作：

$tmp = array_map('json_encode', $merge_json); // Encode everyone array members.
$tmp = array_unique($tmp); // Filter duplicated
$tmp = array_values($tmp); // Re generate array indexes
$tmp = json_encode($tmp);
echo $tmp;

结果：

[{"name":"A1","phone":"123"}","{"name":"A2","phone":"456"}","{"name":"A3","phone":"789"}]

Answer 3

试试这个：

<强>更新

func setupView() {
        session = AVCaptureSession()
        let tap = UITapGestureRecognizer(target: self, action: #selector(self.resume))
        addGestureRecognizer(tap)

        // Set the captureDevice.

        let videoCaptureDevice = AVCaptureDevice.defaultDevice(withMediaType: AVMediaTypeVideo)

        // Create input object.

        let videoInput: AVCaptureDeviceInput?

        do {
            videoInput = try AVCaptureDeviceInput(device: videoCaptureDevice)
        } catch {
            return
        }

        // Add input to the session.

        if (session!.canAddInput(videoInput)) {
            session!.addInput(videoInput)
        } else {
            scanningNotPossible()
        }

        // Create output object.

        let metadataOutput = AVCaptureMetadataOutput()

        // Add output to the session.

        if (session!.canAddOutput(metadataOutput)) {
            session!.addOutput(metadataOutput)

            // Send captured data to the delegate object via a serial queue.

            metadataOutput.setMetadataObjectsDelegate(self, queue: DispatchQueue.main)

            // Set barcode type for which to scan: EAN-13.

            metadataOutput.metadataObjectTypes = [
                AVMetadataObjectTypeCode128Code
            ]

        } else {
            scanningNotPossible()
        }

        // Determine the size of the region of interest

        let x = self.frame.origin.x/UIScreen.main.bounds.width
        let y = self.frame.origin.y/UIScreen.main.bounds.height
        let width = self.frame.width/UIScreen.main.bounds.height
        let height = self.frame.height/UIScreen.main.bounds.height
        let scanRectTransformed = CGRect(x: x, y: y, width: 1, height: height)
        metadataOutput.metadataOutputRectOfInterest(for: scanRectTransformed)


        // Add previewLayer and have it show the video data.

        previewLayer = AVCaptureVideoPreviewLayer(session: session)
        previewLayer.frame = self.bounds
        previewLayer.videoGravity = AVLayerVideoGravityResizeAspectFill
        layer.addSublayer(previewLayer)



        // Begin the capture session.
        session!.startRunning()
    }

Json结果：

$json1 = '[{"name":"A1","phone":"123"}, {"name":"A2","phone":"456"}]';
$json2 = '[{"name":"A1","phone":"123"}, {"name":"A3","phone":"789"},    {"name":"A1","phone":"000"}]';
$array = array_unique(array_merge(json_decode($json1, true), json_decode($json2, true)), SORT_REGULAR);

function data_uniquely($key, $array) {
   $_array = array();
   foreach ($array as $v) {
      if (isset($_array[$v[$key]]))
         continue;
      $_array[$v[$key]] = $v;
   }
   $array = array_values($_array);
   return json_encode($array);
}
$json = data_uniquely('name', $array);
echo $json;

在php中唯一合并json数据

3 个答案: