Question

我有这个JSON，它具有相同的ord_name，cust_id，Ord_num

{"orders":[{"id":"1","ord_name":"Nestea Bottle","ord_desc":"Nestea in a bottle","ord_price":"15","ord_qty":"2","customer_id":"54feec24bff73","ord_num":"13211554feec24bff73","price_x_quan":"30.00","image":"http://192.168.43.52/MMOS/uploads/nestea_bottled.jpg","subtotal":"","imgimg":"uploads/nestea_bottled.jpg"},{"id":"2","ord_name":"Nestea Bottle","ord_desc":"Nestea in a bottle","ord_price":"15","ord_qty":"4","customer_id":"54feec24bff73","ord_num":"13211554feec24bff73","price_x_quan":"60.00","image":"http://192.168.43.52/MMOS/uploads/nestea_bottled.jpg","subtotal":"","imgimg":"uploads/nestea_bottled.jpg"},{"id":"3","ord_name":"Nestea Bottle","ord_desc":"Nestea in a bottle","ord_price":"15","ord_qty":"1","customer_id":"54feec24bff73","ord_num":"13211554feec24bff73","price_x_quan":"15.00","image":"http://192.168.43.52/MMOS/uploads/nestea_bottled.jpg","subtotal":"","imgimg":"uploads/nestea_bottled.jpg"}],"o_total":[{"total":"105"}]}

我的问题是，如何合并或只是以编程方式覆盖JSON与'相同'ord_num，customer_id和ord_name

将更新的字段为qty = 7，price_x_quan

我想要的：瓶中的Nestea将有qty = 7，price_x_quan = 105

这是我的orderhow代码

    <?php
mysql_connect('localhost','root','')or die ('No Connection');
mysql_select_db('dbmoms');

//$ord  = $arr['ord_num']
$sum=0;
$total = $sum;


$sql1 ="SELECT * FROM orders ORDER BY id desc  LIMIT 1"; 
if($row=mysql_fetch_array(mysql_query($sql1))){
    $order_id=$row['ord_num'];
}
$sql ="SELECT * FROM orders  WHERE ord_num = '$order_id' "; 


$result = mysql_query($sql);
$arr["orders"] = array();
    while($row = mysql_fetch_assoc($result)){
    $arr['orders'][]= $row ;
    $sum = $sum+$row['price_x_quan'];




}
$arr['o_total'][] = array('total' => "$sum" );


$json_encoded_string = json_encode($arr); 
 $json_encoded_string = str_replace("\\/", '/', $json_encoded_string);

echo $json_encoded_string;



?>

请帮忙！

Answer 1

以上：

$arr['orders'][]= $row ;

把：

// Specify custom values for Nestea..
if( $row[ 'ord_desc' ] == 'Nestea in a bottle' )
{
    $row[ 'ord_qty' ] = '7';
    $row[ 'price_x_quan' ] = '105.00';

}

Answer 2

您可以使用带有GROUP BY子句的SUM函数在MySQL查询中执行此操作。

作为旁注，您应该考虑使用mysqli（尾随 i 代表改进）或PDO来访问您的数据库，而不是deprecated mysql接口。 Now why on earth should I bother to do that?

$sql1 ="SELECT * FROM orders ORDER BY id desc  LIMIT 1";
if($row=mysql_fetch_array(mysql_query($sql1))){
    $order_id=$row['ord_num'];
}

// Use SUM and GROUP BY to let the database do the math, introducing
// the calculated 'sum_price_x_quan' and 'sum_ord_qty' columns
$sql = "
    SELECT    ord_num,
              ord_desc,
              sum(price_x_quan) as sum_price_x_quan,
              sum(ord_qty)      as sum_rod_qty
    FROM      orders
    WHERE     ord_num = '$order_id'
    GROUP BY  ord_num
";

$result = mysql_query($sql);

$arr = array();
if ($row = mysql_fetch_assoc($result)) {
    $arr['orders'][] = $row ;
    $arr['o_total'][] = array('total' => $row["sum_price_x_quan"]);
}

$json_encoded_string = json_encode($arr);

echo $json_encoded_string;

输出：

{
    "orders":  [
        {
            "ord_num":          "13211554feec24bff73",
            "ord_desc":         "Nestea in a bottle",
            "sum_price_x_quan": "105.00",
            "sum_ord_qty":      "7"
        }
    ],
    "o_total": [
        {
            "total": "105.00"
        }
    ]
}

JSON PHP合并相同的插入数据

2 个答案: