如何在2D阵列中标记连接的组件?

时间:2017-02-28 09:46:59

标签: javascript java 2d flood-fill connected-components

我有这样的2d数组:

0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 0 0 1 1 1 0 1 1 0 1 0 0 0 0 0 1 0 0 1 0 1 0 1 1 0 1 0 1 1 1 0 1 0 0 1 0 1 0 0 0 0 1 0 1 0 1 0 1 0 0 1 0 1 0 0 0 0 1 0 1 0 1 0 1 0 0 1 1 1 0 0 0 0 1 0 1 0 1 0 1 0 0 0 0 0 1 1 1 0 1 0 1 1 1 0 1 0 0 0 0 0 1 0 1 0 1 0 0 0 0 0 1 0 0 0 0 0 1 1 1 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 0 0 0 0 1 1 1 1 0 0 0 1 0 0 0 1 0 0 0 0 1 0 0 1 0 0 0 1 0 1 1 1 1 1 0 0 1 1 1 1 0 0 0 1 0 1 0 1 0 1 0 0 1 1 1 1 0 0 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0

我想将连接的组件(4个方向)标记为:

0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 0 0 2 2 2 0 3 3 0 1 0 0 0 0 0 1 0 0 2 0 2 0 3 3 0 1 0 4 4 4 0 1 0 0 2 0 2 0 0 0 0 1 0 4 0 4 0 1 0 0 2 0 2 0 0 0 0 1 0 4 0 4 0 1 0 0 2 2 2 0 0 0 0 1 0 4 0 4 0 1 0 0 0 0 0 5 5 5 0 1 0 4 4 4 0 1 0 0 0 0 0 5 0 5 0 1 0 0 0 0 0 1 0 0 0 0 0 5 5 5 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 6 6 6 6 6 0 0 0 0 7 7 7 7 0 0 0 6 0 0 0 6 0 0 0 0 7 0 0 7 0 0 0 6 0 6 6 6 6 6 0 0 7 7 7 7 0 0 0 6 0 6 0 6 0 6 0 0 7 7 7 7 0 0 0 6 6 6 6 6 6 6 0 0 0 0 0 0 0 0 0 6 6 6 6 6 6 6 0 0 0 0 0 0 0 0

请帮我解决这个问题。谢谢!!!(java或javascript代码示例会很棒)

1 个答案:

答案 0 :(得分:1)

首先,将1的值更改为-1,因为您需要使用1作为标记。

然后,您可以迭代元素并执行检查,如果它具有标记-1,则将其更改为实际值。继续使用右边和底部的元素。

如果找到了元素,则增加值。

function test(array, i, j, value) {
    if (array[i] && array[i][j] === -1) {
        array[i][j] = value;
        test(array, i + 1, j, value);
        test(array, i, j + 1, value);
        return true;
    }
}

var data = [[0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1], [0, 0, 1, 1, 1, 0, 1, 1, 0, 1, 0, 0, 0, 0, 0, 1], [0, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1], [0, 0, 1, 0, 1, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1], [0, 0, 1, 0, 1, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1], [0, 0, 1, 1, 1, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1], [0, 0, 0, 0, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1], [0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1], [0, 0, 0, 0, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 1, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0], [0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0], [0, 1, 0, 1, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 0, 0], [0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 1, 1, 1, 1, 0, 0], [0, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0], [0, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0]],
    value = 1;

data.forEach(function (a) {
    a.forEach(function (b, i, bb) {
        bb[i] = -b;
    });
});

data.forEach(function (a, i, aa) {
    a.forEach(function (b, j, bb) {
        test(aa, i, j, value) && value++;
    });
});

document.getElementById('out').innerHTML = data.map(function (a) { return a.join(' '); }).join('\n');
<pre id="out"></pre>