Question

因此，编译器一直说“输入”永远不会关闭。但是，程序运行并执行。我只是想知道为什么一直这么说。这是语法。提前谢谢。

import java.util.Scanner;
public class Problem1 {

    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter three numbers: ");
        int N1 = input.nextInt();
        int N2 = input.nextInt();
        int N3 = input.nextInt();       
        DoSort(N1, N2, N3);


    }
    public static void DoSort(int N1, int N2, int N3){

        if ((N1 < N2) && (N2 < N3)){
            System.out.println("The acsending order is " + N1 + " " + N2 + " " + N3);
            }
        if ((N1 > N2) && (N2 > N3)){
            System.out.println("The acsending order is " + N3 + " " + N2 + " " + N1);
            }
        if ((N1 < N2) && (N2 > N3) && (N1 < N3)){
            System.out.println("The acsending order is " + N1 + " " + N3 + " " + N2);
            }
        if ((N1 < N2) && (N2 > N3) && (N1 > N3)){
            System.out.println("The acsending order is " + N3 + " " + N1 + " " + N2);
            }

        }
    }

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Answer 1

这只是一个警告，遗憾的是不适用于你的情况，因为你真的不想关闭System.in。

在该行之前添加@SuppressWarnings("resource")（它也应该是快速修复）以消除警告。

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