Question

我正在为我做一件小事，从截屏应用程序上传文件到我的网络服务器（如果重要的话，ShareX，那么安全性不是很重要，但它仍然在我的脑海中）而且我有无法让上传的文件生效。系统生成一个唯一的5个字符的字母数字字符串，用于将图像保存在（la i.imgur.com/aaaaa）下，并将其存储在SQL数据库中，以便在用户查看时进行检索。该系统还可用作链接缩短器，其链接存储在该行的value列中。

上传的图片应该存储在该5字符随机名称下，并带有原始上传文件的扩展名。移动文件的名称放在value列下，以便稍后检索。

使用测试HTML表单上传文件会将以下内容放入apache错误日志中：

PHP Warning:  move_uploaded_file({webroot}/i/uploads/mS1H6.png): failed to open stream: No such file or directory in {webroot}/i/index.php on line 48
PHP Warning:  move_uploaded_file(): Unable to move '/tmp/phpKAoPjZ' to '{webroot}/i/uploads/mS1H6.png' in {webroot}/i/index.php on line 48

上传者文件的代码如下（该文件夹的所有传入请求都.htaccess到此文件中）：

require("./uploader_settings.inc.php");

$conn = mysqli_connect($db_url,$db_user,$db_pass,$db_database);
if (mysqli_connect_errno()) {
    http_response_code(500); //server error
    die();
}
//handle content
if ($_SERVER['REQUEST_METHOD'] == 'POST') {

    {sanity checks}

    //actually do it
    $value =  $_POST['value'];
    $random = random_str(5);
    do {
        $query = mysqli_query($conn,"SELECT COUNT(*) FROM ".$db_table." WHERE shortened = '".$random."';");
        if ($query != 0) {
            break;
        } else {
            $random = random_str(5);
        }
    } while (true);
    switch ($_POST['type']) {
        case "url":
            {not applicable}
        case "text":
            {not applicable}
        case "file":
            var_dump($_FILES);
            $file = $_FILES['fileToUpload'];
            $newfile = realpath(dirname(__FILE__))."/uploads/".$random.".".mysqli_real_escape_string($conn,pathinfo($file['name'],PATHINFO_EXTENSION));
            if (!move_uploaded_file($file['tmp_name'],$newfile)) {
                http_response_code(500);
                echo "File error!";
                die();
            }
            mysqli_query($conn,"INSERT INTO ".$db_table." (shortened,type,value) VALUES ('".$random."','file','".$newfile."');");
            break;
    }
    http_response_code(200);
    echo $upload_returnURL.$random;
    die();
} else { //getting a URL
    $query = mysqli_query($conn,"SELECT * FROM ".$db_table." WHERE shortened = '".mysqli_real_escape_string($conn,$_GET['selector'])."';");
    if (mysqli_num_rows($query) > 0) {
        $array = mysqli_fetch_array($query);
        $value = $array['value'];
        switch ($array['type']) {
            case "url":
                header("Location: ".$value);
                die();
            case "text":
                break;
            case "file":
                fpassthru(fopen($value,"rb"));
                die();
        }
    } else {
        header("Location: ".$upload_failRedirect);
        die();
    }
}

感谢任何帮助，谢谢！

PHP move_uploaded_file（）无法正常工作（无法打开流）

0 个答案: