Question

这是我必须回答的问题：

编写程序以输入考试成绩（满分100分），直到您输入“退出”。完成考试成绩后，课程将打印出所有考试成绩的平均值。

HINTS：要计算出平均值，您必须保持考试分数的总计和输入数字的计数。尝试使程序工作一次，然后找出退出条件并使用while True：循环。

示例运行：输入考试成绩或输入“退出”：100 输入考试成绩或输入“退出”：100 输入考试成绩或输入“退出”：50 输入考试成绩或输入“退出”：退出得分数3.平均分为83.33

这是我的代码：

count = 0
average = sum
while True:
    num =input('Enter an exam score or type "quit":')
    count = count + 1
    average = sum(num)
    print ('the total of exams is %d and the average is %f' % count, average)
    if num == 'quit':
        break
print ('this is ok for now')

Answer 1

这一行存在很多问题：public class MailParam { private String username; String pwd; String auth; String startls; String host; String port; String from; String replyto; String logopath; public String getAuth() { return auth; } public String getHost() { return host; } public String getPort() { return port; } public String getPwd() { return pwd; } public String getStartls() { return startls; } public String getUsername() { return username; } public String getFrom() { return from; } public String getReplyto() { return replyto; } public String getLogopath() { return logopath; } public void setAuth(String val) { auth = val; } public void setHost(String val) { host = val; } public void setPort(String val) { port = val; } public void setPwd(String val) { pwd = val; } public void setStartls(String val) { startls = val; } public void setUsername(String val) { username = val; } public void setFrom(String val) { from = val; } public void setReplyto(String val) { replyto = val; } public void setLogoPath(String val) { logopath = val; } }。

average = sum(num)的适当输入是要求和的数字列表。在您的情况下，您只需要一个数字或单词“quit”。

您需要做的是跟踪计数和总计，然后在最后进行划分：

sum

Answer 2

我的观点是使用statistics模块和sys退出。还处理非int（或非浮点）输入并打印正确的消息，而不是退出ValueError

import statistics, sys

notes = []
count = 0
average = 0   # or None
while True:
    note = input('Enter score: ')
    # handle quit request first, skip any calculation
    # if quit is the first request
    if note == 'quit':
        print('Program exit. Average is %s' % average)
        sys.exit()
    else:
        # test if the entered data can be an int or float
        try:
            note = int(note)     # can be replaced with float(note) if needed
            count += 1           # increase the counter
            notes.append(int(note))
            average = statistics.mean(notes)    # calculate the average (mean)
            print('Total %s average is %s' % (count, average))
        # just print an error message otherwise and continue
        except ValueError:
            print('Please enter a valid note or "quit"')

我收到此语法错误：TypeError：+：'int'和'str'

2 个答案: