Question

我试图从列表中找到三个数字的平均分数，如下所示：

a = (lines.split(":")[1].split(",")[-3:])
Print (a)
Averagescore = sum(a)/len(a)
Print (averagescore)

然后它说： /＆＃39; str＆＃39;的类型错误不支持的操作数类型和＆＃39; int＆＃39;

Answer 1

我怀疑您描述的错误消息可能对此代码不准确，但问题是您尝试将字符串列表视为整数列表。例如

>>> s = "1 16 32" # string
>>> s.split() # this returns a list of strings
['1', '16', '32']
>>> s.split()[0] + 1 # you can't add an int to a string
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: Can't convert 'int' object to str implicitly

如果您想将它们视为整数（或浮点数），那么您需要添加转换，如

a = [int(n) for n in s.split()]
a = [float(n) for n in s.split()] # alternatively

/＆＃39; str＆＃39;的类型错误不支持的操作数类型和＆＃39; int＆＃39;

1 个答案: