我的python程序一直在返回" KeyError:20"

时间:2017-02-25 16:24:09

标签: python python-3.x dictionary keyerror

我已经在python中编写了一个程序,该程序应该返回每个级别的得分最高的玩家,但它会一直返回" KeyError:20"对于第69行(P_L1 = players_TS [H_L1]),我无法解决如何解决这个问题。在我的代码中,我打开了一个名为" playerScores.txt"的文本文件。格式如下:
月亮,3,15
StarPlayer,2,18
艾莉,5,9

这是我的代码:

    print("The highest scorers for each leve are:\n")
    PS3=open("PlayerScores.txt","r").read().split("\n")
    level1_scores=[]
    players_TS={}
    level2_scores=[]
    players_T2={}
    level3_scores=[]
    players_T3={}
    level4_scores=[]
    players_T4={}
    level5_scores=[]
    players_T5={}

    for line in PS3:
        lines=line.split(",")
        player=lines[0]
        level=lines[1]
        score=lines[2]

        erros=open("scoreboard_errorlog.text","w")

        if int(score)>20:
            errors.write(score)
        if int(level)>5:
            errors.write(level)

        if int(level)==1:
            level1_scores.append(int(score))
            players_TS.setdefault(score,[]).append(player)
        if int(level)==2:
            level2_scores.append(int(score))
            players_T2.setdefault(score,[]).append(player)
        if int(level)==3:
            level3_scores.append(int(score))
            players_T3.setdefault(score,[]).append(player)
        if int(level)==4:
            level4_scores.append(int(score))
            players_T4.setdefault(score,[]).append(player)
        if int(level)==5:
            level5_scores.append(int(score))
            players_T5.setdefault(score,[]).append(player)

    H_L1=max(level1_scores)
    P_L1=players_TS[H_L1]
    H_L2=max(level2_scores)
    P_L2=players_T2[H_L2]
    H_L3=max(level3_scores)
    P_L3=players_T3[H_L3]
    H_L4=max(level4_scores)
    P_L4=players_T4[H_L4]
    H_L5=max(level5_scores)
    P_L5=players_T5[H_L5]

    print("Level\tPlayer name\tScore\nLevel 1\t",P_L1,"\t",H_L1,"\nLevel 2\t",P_L2,"\t",H_L2,"\nLevel 3\t",P_L3,"\t",H_L3,"\nLevel 4\t",P_L4,"\t",H_L4,"\nLevel 5\t",P_L5,"\t",H_L5)

非常感谢帮助。

1 个答案:

答案 0 :(得分:2)

问题出现在这里:

if int(level)==1:
    level1_scores.append(int(score))
    players_TS.setdefault(score,[]).append(player)

假设score == "20"。您正在将整数 20添加到level1_scores,但使用字符串 "20"作为players_TS中的密钥。然后,当你到达这些行

H_L1=max(level1_scores)
P_L1=players_TS[H_L1]

H_L1是整数值20,但players_TS中的所有键都是"20"之类的字符串。自20 != "20"起,KeyError结果。

可能,您希望score(和level,就此而言)是一个整数,所以在解析之后立即转换一次,然后按原样使用score在循环的其余部分。

for line in PS3:
    lines = line.split(",")
    player = lines[0]
    level = int(lines[1])
    score = int(lines[2])

    with open("scoreboard_errorlog.text","w") as errors:

        if score > 20:
            errors.write(score)
        if level > 5:
            errors.write(level)

    if level == 1:
        level1_scores.append(score)
        players_TS.setdefault(score,[]).append(player)
    elif level == 2:
        level2_scores.append(score)
        players_T2.setdefault(score,[]).append(player)
    elif level == 3:
        level3_scores.append(score)
        players_T3.setdefault(score,[]).append(player)
    elif level == 4:
        level4_scores.append(score)
        players_T4.setdefault(score,[]).append(player)
    elif level == 5:
        level5_scores.append(score)
        players_T5.setdefault(score,[]).append(player)

    H_L1 = max(level1_scores)
    P_L1 = players_TS[H_L1]
    H_L2 = max(level2_scores)
    P_L2 = players_T2[H_L2]
    H_L3 = max(level3_scores)
    P_L3 = players_T3[H_L3]
    H_L4 = max(level4_scores)
    P_L4 = players_T4[H_L4]
    H_L5 = max(level5_scores)
    P_L5 = players_T5[H_L5]

但是,您还应该使用dict来存储大量此类数据,而不是单独命名的变量。

level_scores = {level: [] for level in range(1,6)}
players = {}
for line in PS3:
    lines = line.split(",")
    player = lines[0]
    level = int(lines[1])
    score = int(lines[2])

    # Use append mode, or you overwrite the file each time through the loop
    with open("scoreboard_errorlog.text", "a") as errors:

        if score > 20:
            errors.write(score)
        if level > 5:
            errors.write(level)
            continue

    level_scores[level].append(score)
    players[level].setdefault(score,[]).append(player)


H = {}
P = {}
for level in range(1,6):
    H[level] = max(level_scores[level])
    P[level] = players[level][H[level]]