Question

我们应该创建一个程序，对于正整数n，n的阶乘

factorial_cap（1）→1 ......＃1！= 1

这是我的代码。

def factorial(num):
F = 0
x = 1
factor = 1
while (F <= num):
    for i in range(1,x + 1):
        factor = (factor * i)
        if (F>=num):
            return x
        else:
            x = x+1
    print("The answer is", x)
    F = factor

factorial_cap（24）我只是使用print语句来查看输出是什么，它一直在给我答案是2 答案是4 答案是8，虽然正确的答案应该是4，但我无法阻止它循环而只返回值4

Answer 1

它继续打印＆＃34;答案的原因是＆＃34; string是print语句直接放在while循环中，所以它会触发每次新的尝试。

尝试这种方法（Python 2.7.8）：

def factorial_cap(num):
    print "Input number:", num
    F = 1
    x = 1
    while (F < num):
        x += 1
        F *= x

    print "The answer is:", x
    return x

for t in xrange(0,30):
    factorial_cap(t)
    print

或者这个（效率较低）：

def factorial(num):
    res = 1
    for i in xrange(1,num+1):
        res *= i
    return res

def factorial_cap(num):
    print "Input number:", num
    F = 0
    x = 0
    while (F < num):
        x = x+1
        F = factorial(x)

    print "The answer is:", x
    return x

for t in xrange(0,30):
    factorial_cap(t)
    print

我的python程序不断返回错误的值

1 个答案: