出于某种原因,我的在线和桌面编译环境都认为一切都是无效的语法突然!这是我的代码:
def sumn(n): #summation for sigma
return ((n + 1) * n) / 2
ipt = raw_input('How In Depth Would You Like To Go? ')
ipt = int(ipt)
pi = sumn(ipt) * ((4 / (8 * ipt + 1)) - (2 / (8 * ipt + 4)) - (1 / (8 * ipt + 5)) - (1 / (8 * ipt + 6)) * (1 / (16 ^ ipt))
print pi
答案 0 :(得分:0)
sumn(n)
的缩进无效。ipt = int(raw_input('How In Depth Would You Like To Go? '))
不正确。**
代替^
。我的代码使用pi
的正确缩进和语法:
>>> def sumn(n): #summation for sigma
return ((n + 1) * n) / 2
>>> ipt = float(raw_input('How In Depth Would You Like To Go? '))
How In Depth Would You Like To Go? 4
>>> pi = sumn(ipt) * ((4 / (8 * ipt + 1)) - (2 / (8 * ipt + 4)) - (1 / (8 * ipt + 5)) - (1 / (8 * ipt + 6)) * (1 / (16 ** ipt)))
>>> print pi
0.386291370825
答案 1 :(得分:0)
Yayy,我终于解决了!
from decimal import *
def sumn(n): #summation for sigma
return ((n + 1) * n) / 2
ipt = int(raw_input('How In Depth Would You Like To Go? '))
getcontext().prec = ipt
def factorial(n):
if n<1:
return 1
else:
return n * factorial(n-1)
def BBP(n):
pi = Decimal(0)
k = 0
while k < n:
pi += (Decimal(1) / (16 ** k)) * ((Decimal(4) / (8 * k + 1)) - (Decimal(2) / (8 * k + 4)) - (Decimal(1) / (8 * k + 5)) - (Decimal(1) / (8 * k + 6)))
k += 1
return pi
print BBP(ipt)
离。
How In Depth Would You Like To Go? 1000
3.141592653589793238462643383279502884197169399375105820974944592307816406286208998628034825342117067982148086513282306647093844609550582231725359408128481117450284102701938521105559644622948954930381964428810975665933446128475648233786783165271201909145648566923460348610454326648213393607260249141273724587006606315588174881520920962829254091715364367892590360011330530548820466521384146951941511609433057270365759591953092186117381932611793105118548074462379962749567351885752724891227938183011949129833673362440656643086021394946395224737190702179860943702770539217176293176752384674818467669405132000568127145263560827785771342757789609173637178721468440901224953430146549585371050792279689258923542019956112129021960864034418159813629774771309960518707211349999998372978049951059731732816096318595024459455346908302642522308253344685035261931188171010003137838752886587533208381420617177669147303598253490428755468731159562863882353787593751957781857780532171226806613001927876611195909216420193
最后两个值通常是错误的,我仍在尝试截断它们。然后我所要做的就是在ipt上加2,这将花费我5秒钟的时间☺