我在swift 3中有以下代码:
class StringUtility {
static func Localizer(tableName: String?) -> (_ key: String, _ params: CVarArg...) -> String {
return { (key: String, params: CVarArg...) in
let content = NSLocalizedString(key, tableName: tableName, comment: "")
if params.isEmpty {
return content
}
print(params) ->>>>>> this prints [[[Wells Fargo]]]
return NSString.init((format: content, arguments: getVaList(params))) as String
}
}
}
func localizationHelper(tableName: String, key: String, params: CVarArg...) -> String {
let t = StringResourceUtility.Localizer(tableName: tableName)
print(params) - >>>>>>>>>> this prints [[Wells Fargo]]
return t(key, params)
}
如果在上面两个函数中看到print语句,每次在函数内部传递CVarArg时都会附加[],导致输出错误的本地化字符串。
1)CVarArg不能像上面代码一样多次传递? 2)如何解决这个问题?
答案 0 :(得分:8)
你不能将变量参数列表传递给另一个函数
必须通过CVaListPointer
。另外withVaList
应该
用来代替getVaList
:
class StringResourceUtility {
static func Localizer(tableName: String?) -> (_ key: String, _ params: CVaListPointer) -> String {
return { (key: String, params: CVaListPointer) in
let content = NSLocalizedString(key, tableName: tableName, comment: "")
return NSString(format: content, arguments: params) as String
}
}
}
func localizationHelper(tableName: String, key: String, params: CVarArg...) -> String {
let t = StringResourceUtility.Localizer(tableName: tableName)
return withVaList(params) { t(key, $0) }
}
示例:
let s = localizationHelper(tableName: "table", key: "%@ %@", params: "Wells", "Fargo")
print(s) // Wells Fargo