Question

我必须在python中创建一个幸运的名字编号程序，但我一直遇到很多错误。如果你不知道一个幸运的名字是什么，它基本上是字母表中的每个字母都有一个值，你在你的名字和第二个名字中加上toether值，例如约翰多伊

    165  465
    1+6+5 = 12
    4+6+5 = 15
    15 + 12 = 27
    2+7 = 8
    then 8 = has diplomatic skills

这是我到目前为止所做的：


     #this will go all the way to z
    charDict = { 'A' : 1, 'B' : 2, 'C' : 3, 'D' : 4} 

    # example names - while loop will go here
    firstName = 'AAB'
    lastName = 'DCDD'

    # split the strings into a list of chars
    firstNameChars = list(firstName)
    lastNameChars = list(lastName)

    # sum up values
    firstNameSum = 0
    lastNameSum = 0
    for chr in firstNameChars:
        firstNameSum += charDict[chr]
    for chr in lastNameChars:
        lastNameSum += charDict[chr]

    # cast sums to strings. In this example, this would be '2024'
    combinedNames = str(firstNameSum) + str(lastNameSum)

    # split the string into a list of chars
    combinedNameDigits = list(combinedNames)

    # sum them up
    finalSum = 0
    for dgt in combinedNames:
        finalSum += int(dgt)

    # print the lucky number
    print finalSum

所以我的问题是，我从哪里开始，因为数字没有正确加起来并且字母的值不正确，所以基本上我如何正确地进行计算< / p>

Answer 1

考虑到你总是将你的数字分成数字级别，我会让你把它包装在一个函数中并修改字典以添加其他字母

first = 'aaa'
last = 'bbb'
name = first + last
dicti = {'a':1, 'b':2, '1':1, '2':2 ,  '3':3 ,  '4':4 ,  '5':5 ,  '6':6 ,
            '7':7 ,  '8':8 ,  '9':9 ,  '0':0}
while len(name) >1:
    sum = 0
    for letter in name:
        sum = sum + dicti[letter]
    name = str(sum)
final_sum = int(name)

Python中幸运的名字号码挑战

1 个答案: