我想在每个乘客的链表中输入一组新的节点。 例如:
对于乘客姓名,我输入约翰。
对于国家/地区代码,我输入:BI
对于航班号,我输入:095
对于行李数量,我可以输入任何金额。
假设我输入:John,BI,095,3。
这就是我得到的:[John with baggage(s) [BI0950, BI0951, BI0952]]
这就是我想要的。
然后我按'b'进入新乘客。
然后我进入下一位乘客:Jane,BU,096,3。
这就是我得到的:[John with baggage(s) [BI0950, BI0951, BI0952], Jane with baggage(s) [BI0950, BI0951, BI0952, BU0960, BU0961, BU0962]]
每当我点击'b'('b'是添加新乘客)时,如何从baggage
链接列表中删除旧节点(BI0950,BI0951,BI0952)?
import java.util.*;
public class baggage_system{
static LinkedList<String> baggagex = new LinkedList<String>();
public static String getUser_command(){
Scanner keyboard = new Scanner(System.in);
System.out.print("Enter command B-baggage, n-next, q-quit");
String s = keyboard.nextLine();
return s;
}
public static String getUser_flight(){
Scanner keyboard = new Scanner(System.in);
System.out.println("Please enter the flight number");
String s = keyboard.nextLine();
return s;
}
public static String getPassenger(){
Scanner keyboard = new Scanner(System.in);
System.out.println("Please enter passenger name");
String s = keyboard.nextLine();
return s;
}
public static String getUser_country(){
Scanner keyboard = new Scanner(System.in);
System.out.println("Please enter the country code");
String s = keyboard.nextLine();
return s;
}
public static int getUser_number(){
Scanner keyboard = new Scanner(System.in);
System.out.println("Please enter number of baggage");
int s = keyboard.nextInt();
return s;
}
public static String nextbg(ListIterator<String> iteratorbg){
return iteratorbg.next();
}
public static LinkedList<String> makeBaggage(String country, String flight, int num){
baggagex.add(country + flight + num);
return baggagex;
}
public static int count(){
System.out.println(baggagex.size());
return baggagex.size();
}
public static void main(String args[]) {
LinkedList<Passenger> passenger = new LinkedList<Passenger>();
LinkedList<String> baggage = new LinkedList<String>();
ListIterator<String> iteratorbg = baggage.listIterator();
LinkedList<String> counting = new LinkedList<String>();
String command = "";
while (!command.equals("q")){
command = getUser_command();
if(command.equals("B") || command.equals("b")){
String p = "";
p = getPassenger();
passenger.add(new Passenger(p));
String country = "";
country = getUser_country();
String flight = "";
flight = getUser_flight();
int amount = 0;
amount = getUser_number();
String[] bg = new String[amount];
for(int i = 0; i < amount; i++){
// LinkedList<String> bgg = new LinkedList<String>();
baggage = makeBaggage(country, flight, i);
System.out.println(baggage);
}
LinkedList<String> bgg = new LinkedList<String>(baggage);
passenger.getLast().setBaggages(bgg);
System.out.println(passenger);
/* if(baggage.size() != 0 && baggage.size() > baggage.size() - 1){
for(int j = 0; j < bgg.size(); j++){
baggage.remove(j);
}
*/
// System.out.println(bgg);
/* while (!baggage.isEmpty()) {
baggage.removeFirst();
}
*/
} else if(command.equals("n")){
count();
} else if (command.equals("p")){
System.out.println(baggage.peekFirst());
}
else
System.out.println("Enter 'q' to end the program");
}
}
public static class Passenger {
String passengers;
List<String> baggage;
public Passenger(String passengers) {
this.passengers = passengers;
baggage = null;
}
public void setBaggages(List<String> baggages) {
this.baggage = baggages;
}
public void pBags(){
}
@Override
public String toString() {
return passengers + " with baggage(s) " + baggage;
}
}
}
答案 0 :(得分:1)
问题在于您的编码逻辑,您为所有乘客使用相同的链表行李对象。
static LinkedList<String> baggagex = new LinkedList<String>();
如果您在此LinkedList中添加或删除任何对象,它将影响所有乘客。
解决方案: 为每位乘客使用新的链表对象。如下代码:
public static LinkedList<String> makeBaggage(String country, String flight, int num)
{
LinkedList baggagex = new LinkedList();
baggagex.add(country + flight + num);
return baggagex;
}