Question

节点必须具有哪些属性，以便在graphml中显示其名称。 GRAFIC？

我根据包

创建了一些节点

MATCH (artifact:Artifact)
WHERE
   artifact.type <> "test-jar"
MATCH
  (artifact:Artifact)-[:CONTAINS]->(root:Package{fqn:"net.sf.sze.dao.api"})-[:CONTAINS]->(slice:Package)
WITH COLLECT(slice) AS rows1
MATCH
  (artifact:Artifact)-[:CONTAINS]->(root:Package{fqn:"net.sf.sze.frontend"})-[:CONTAINS]->(slice:Package)
WITH rows1 + COLLECT(slice) AS rows2
MATCH
  (artifact:Artifact)-[:CONTAINS]->(root:Package{fqn:"net.sf.sze.service"})-[:CONTAINS *2..2]->(slice:Package)
WITH rows2 + COLLECT(slice) AS rows3
UNWIND rows3 AS slice
MERGE (sn:Slice{name:slice.name})
MERGE (sn)-[:SLICE_CONTAINS]-> (slice)
RETURN
  sn

并尝试使用

创建graphml图表

MATCH
  (slice1:Slice)-[:SLICE_CONTAINS]->()-[:CONTAINS*]->(t1:Type),
  (slice2:Slice)-[:SLICE_CONTAINS]->()-[:CONTAINS*]->(t2:Type),
  (t1)-[d:DEPENDS_ON]->(t2)
WHERE
   slice1 <> slice2
WITH
  slice1, slice2, count(d) as weight
RETURN
  slice1 as Slice1, slice2 as Slice2, {
    role :     "relationship",
    type :     "DEPENDS_ON",
    startNode: slice1,
    endNode:   slice2,
    properties: {
      weight: weight
    }
  } as Dependency

创建的图表很好地期望节点名称。我只得到标签CompositeObject, id = 123456，这使图表无用。

任何人都可以给我一个提示，有什么不对吗？

Answer 1

对于由jQAssistant扫描程序定义的类型，存在将作为标签呈现的类型特定规则，例如， “fqn”代表“：Artifact”标记为节点。

您正在创建无法确定类型的虚拟关系，因此无法显示任何属性。 jQAssistant 1.3.0将支持属性“标签”来控制它，例如

  ....
RETURN
  slice1 as Slice1, slice2 as Slice2, {
    role :     "relationship",
    type :     "DEPENDS_ON",
    startNode: slice1,
    endNode:   slice2,
    label: weight, // set an explicit label
    properties: {
      weight: weight
    }
 } as Dependency

jQassistant中的clean graphml名称必须存在哪些节点属性

1 个答案: