Question

假设我有一些二进制数据被转换为32位整数而不是32位浮点（小端），我该如何纠正？

例如：1155186688应为1750 float（00 C0 DA 44 hex）。

Answer 1

Struct用于将类型打包和解包为字节。

将整数转换回字节，然后转换为float：

>>> my_bytes = struct.pack('I', 1155186688) # 'I' = Unsigned Int
b'\x00\xc0\xdaD'
>>> my_float = struct.unpack('f', my_bytes)[0] # 'f' = float
1750

或长篇：

using Newtonsoft.Json;
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace TestsJson
{
    class Model
    {
        public DateTime Date { get; set; }

        public int Clicks { get; set; }

        public Model(DateTime date, int clicks)
        {
            Date = date;
            Clicks = clicks;
        }
    }

    class Program
    {
        static void Main(string[] args)
        {
            var data = new List<Model>()
            {
                new Model(new DateTime(2017, 01, 21), 14),
                new Model(new DateTime(2017, 01, 22), 17),
                new Model(new DateTime(2017, 01, 23), 50),
                new Model(new DateTime(2017, 01, 24), 0),
                new Model(new DateTime(2017, 01, 25), 2),
                new Model(new DateTime(2017, 01, 26), 0)
            };

            foreach (var model in data)
            {
                var json = "{" + JsonConvert.SerializeObject(model.Date.ToShortDateString()) + ":" + model.Clicks + "}";
                Console.WriteLine(json);
            }

            Console.Read();
        }
    }
}

将整数转换回32位十六进制表示然后浮动？

1 个答案: