Question

以下是我在搜索页面中过滤项目所做的工作：

var braken = document.querySelector(".board li.braken");
    var champagne = document.querySelector(".board li.champagne");

    braken.addEventListener("click", function () {
        braken.classList.remove("braken")
        braken.classList.add("champagne");
    })
    champagne.addEventListener("click", function () {
        champagne.classList.remove("champagne")
        champagne.classList.add("braken")
    })

我想不过滤这些项目，而是按相关性，某种评分指标对其进行排序;选择的标签，字符串等更加巧合 - 分数越高，任务显示越高。

我正在考虑这种疑问：

@experiences = Mission.where(active: true)
@experiences = @experiences.where(accept_families: true) if filter_params['forFamily'].present? && filter_params['forFamily'] == true
@experiences = @experiences.includes(:country_missions).where(:country_missions => { :country_id => filter_params['countries'] }) if filter_params['countries'].present?
@experiences = @experiences.includes(:skill_all).where(:skill_missions => { :skill_id => filter_params['skills'] }) if filter_params['skills'].present?

months = []
months.push(12, 1, 2) if filter_params['start_winter'].present? && filter_params['start_winter'] == true
@experiences = @experiences.joins(:start_dates).includes(:start_dates).where('extract(month from start_dates.start) IN (?)', months) unless months.blank?

但那太简单了;我无法想象如何获得＆＃34;而＃34;每个标签的大小写：例如，每个filter_params [＆＃39; countries＆＃39;]包含一系列ID：[212,30,1]。对于模型项中存在的每个国家/地区，分数增加1。

我该怎么做？

我正在使用Postgres作为数据库。

我已经尝试了类似

的内容

SELECT title, company, user, CASE 
  WHEN upper(company_name) LIKE '%#{word[0].upcase}%' THEN 3
  WHEN upper(company_name) LIKE '%#{company_name.upcase}%' THEN 2
  ELSE 0 END as score      
  FROM selected_tables
  WHERE company_name LIKE '%#{company_name}%'
  ORDER BY score DESC;

但这并不正确。

Answer 1

如果我理解正确，你会找到这样的东西：

SELECT title, company, user,
       CASE WHEN upper(company_name) LIKE '%#{word[0].upcase}%' THEN 3 ELSE 0 END
     + CASE WHEN upper(company_name) LIKE '%#{company_name.upcase}%' THEN 2 ELSE 0 END
      as score      
  FROM selected_tables
 WHERE company_name LIKE '%#{company_name}%'
 ORDER BY score DESC;

按轨道相关性排序

1 个答案: