Question

我用更清晰的样本数据来重述问题，以帮助成员更好地理解我的问题。

我使用linq进行相当基本的查询，但不知道如何编写复杂的查询。我在列表中有这样的数据，

var list = new List<Users>()
{ 
  new Users() { FirstName = "John", LastName= "Doe", MiddleName = "P.", Phone = "111-111-111", Email = "abc@xyz.com" },      
  new Users() { FirstName = "Alex", LastName= "Jones", MiddleName = "S", Phone = "333-333-222", Email = "xyz@abc.com" },   
  new Users() { FirstName = "John", LastName= "Doe", MiddleName = "p.", Phone = "111-111-111", Email = "abc@xyz.com" },   
  new Users() { FirstName = "John", LastName= "Doe", MiddleName = "", Phone = "111-222-111", Email = "abc@xyz.com" },   
  new Users() { FirstName = "John", LastName= "", MiddleName = "", Phone = "111-111-111", Email = "abc@xyz.com" },   
  new Users() { FirstName = "Alex", LastName= "James", MiddleName = "N", Phone = "111-111-111", Email = "cde@xyf.com" },   
  new Users() { FirstName = "Alex", LastName= "Jones", MiddleName = "S", Phone = "333-333-222", Email = "xyz@abc.com" },   
  new Users() { FirstName = "John", LastName= "Doe", MiddleName = "", Phone = "111-222-111", Email = "" }, 
};

这些只是用户的样本记录，有数千条这样的记录。我想对用户进行排序/分组，以便对于单个用户（FirstName，LastName），最顶层的记录将是FirstName，LastName，MiddleName，Phone和Email匹配的记录。在这些记录需要来之后，FirstName，LastName，MiddleName和Phone匹配。因此，具有最匹配列的行将位于顶部，而具有最少匹配列的行将位于底部。单个用户的行不应与其他用户重叠，因此类似的用户记录将在一起。

我尝试过：

我使用了以下Linq查询来实现所需的结果，

obj = obj.OrderBy(x => (chkFirstName.Checked) ? x.FIRSTNAME : "")
                               .ThenBy(x => (chkLastName.Checked) ? x.LASTNAME : "")
                               .ThenBy(x => (chkMiddleName.Checked) ? x.MIDDLENAME : "")
                               .ThenBy(x => (chkPhone.Checked) ? x.PHONE_PRIMARY : "")
                               .ThenBy(x => (chkEmail.Checked) ? x.EMAIL1 : "").ToList();

这不是正确的订单。例如，此查询将为用户将最匹配的列行分组在顶部，然后将为另一个用户分配少量记录。我在想，可能是集团能做到这一点吗？请指导我完成这个。

（注意）：列表中有额外的列我没有提及，但它们不会用于任何排序或分组。

Answer 1

您可以通过

订购

var sorted = list.OrderBy(l => l.FirstName).ThenBy(l => l.LastName).ThenBy(l => l.MiddleName).ToList();

Answer 2

var result = list.OrderBy(t => t.FirstName).ThenBy(t => t.LastName).ThenBy(t => t.MiddleName);

通过维护顺序和相关性将列表中的类似记录分组

2 个答案: