Question

以下是我在BlueJ的摇滚，纸张，剪刀游戏的代码。当我编译并且用户输入输入时，计算机立即从playerWins（）打印许多输出。当用户输入＆＃34;退出＆＃34;时，游戏结束。有人可以帮助我，所以我的屏幕不会被淹没吗？（如果有任何方法可以压缩我的代码也会很棒）。

import java.util.Random;
import java.util.Scanner;

public class RockPaperScissors
{

    public static void main(String[] args)
    {
        int wins = 0, losses = 0, ties = 0;
        boolean output;
        Scanner scan = new Scanner(System.in);
        System.out.print("(R)ock, (P)aper, (S)cissors, or quit: ");
        String playerChoice = scan.nextLine();
        while (playerChoice.equals("quit") == false)
        {      
            playerChoice = playerChoice.toUpperCase();
            String computerChoice = getComputerChoice();
            if(playerChoice.equals(computerChoice) != true)
            {
                output = playerWins(playerChoice, computerChoice);
                if (output == true)
                {
                    wins++;
                }
                else if (output == false)
                {
                    losses++;
                }
            }
            else
            {
                ties++;
                System.out.println("Tie!");
            }
        }
        System.out.println("QUIT");
        System.out.println("Wins: " + wins);
        System.out.println("Losses: " + losses);            
        System.out.println("Ties: " + ties); 
        scan.close();
    }
    public static String getComputerChoice()
    {
        Random gen = new Random();
        int num = gen.nextInt(30) + 1;
        if (num % 3 == 2)
        {
            return "R";
        }
        else if (num % 3 == 1)
        {
            return "P";
        }
        else
        {
            return "S";
        }
    }
    public static boolean playerWins(String playerChoice, String computerChoice)
    {
        if (playerChoice.equals("R") == true)
        {
            if (computerChoice.equals("P") == true)
            {
                System.out.println("My Point! \nP beats R"); // Rock is beaten by paper
                return false;
            }
            else if (computerChoice.equals("S") == true)
            {
                System.out.println("Your Point! \nR beats S"); // Rock beats scissors
                return true;
            }
        }
        else if (playerChoice.equals("P") == true)
        {
            if (computerChoice.equals("R") == true)
            {
                System.out.println("Your Point! \nP beats R"); //Paper beats rock
                return true;
            }
            else if (computerChoice.equals("S") == true)
            {
                System.out.println("My Point! \nS beats P"); //Paper is beaten by scissors
                return false;
            }
        }
        else if (playerChoice.equals("S") == true)
        {
            if (computerChoice.equals("P") == true)
            {
                System.out.println("Your Point! \nS beats P"); //Scissor beats paper
                return true;
            }
            else if (computerChoice.equals("R") == true)
            {
                System.out.println("My Point! \nR beats S"); //Scissors is beaten by rock
                return false;
            }
        }
        return false;
    }
}

Answer 1

这两行是问题所在：

String playerChoice = scan.nextLine();
while (playerChoice.equals("quit") == false) {

您正在阅读一行，然后一遍又一遍地检查该行。您需要在循环中读取内部的新行。你现在拥有它的方式，只是试图无限次地进行相同的移动。

尝试：

String playerChoice = scan.nextLine();
while (playerChoice.equals("quit") == false) {

    //do all of the stuff that is already inside your loop

    playerChoice = scan.nextLine();
}

每次处理完最后一次输入后，这将再次获得用户输入。

Answer 2

您只检查用户输入一次，即在循环之前：

String playerChoice = scan.nextLine();

解决这个问题的一个非常好的方法如下：

String playerChoice;
while((playerChoice = scan.nextLine()).equals("quit") == false)
{
    //more code
}

上述代码的作用是playerChoice在调用.equals("quit")之前设置。如果你使用这种方法，你不需要在循环结束时再设置一行来设置playerChoice，而只需在循环的头部进行。

摇滚，纸，剪刀 - BlueJ疯狂循环

2 个答案: