django rest-farmework嵌套关系使用过滤器

时间:2017-02-19 01:15:14

标签: python django django-rest-framework serializer

使用django rest-farmework来实现API,有一个问题一直无法解决:如何过滤关联的表?,具体代码如下:

models.py

class Category(models.Model):
    name = models.CharField(max_length=30)
    amount = models.IntegerField()

class Source(models.Model):
    name = models.CharField(max_length=50)
    rss_link = models.URLField()
    amount = models.IntegerField()
    # ForeignKey
    category = models.ForeignKey(Category)

views.py

class CategoryListView(APIView):
    def get(self, request):
        category = Category.objects.all()
        serializers = CategorySerializers(category, many=True)
        return Response(serializers.data)

serializers.py

class SourceSerializers(serializers.ModelSerializer):
    class Meta:
        model = Source
        fields = ("id","name","amount")

class CategorySerializers(serializers.ModelSerializer):
    source_set = SourceSerializers(many=True, read_only=True)

    class Meta:
        model = Category
        fields = ("id","name","amount","source")

程序运行结果:

[
    {
        "id": 1,
        "name": "study",
        "amount": "0",
        "source": [
            {
                "id": 34,
                "name": "java",
                "amount": "0"
            },
            {
                "id": 35,
                "name": "python",
                "amount": "0"
            },
            {
                "id": 36,
                "name": "css",
                "amount": "2"
            }
        ]
    }
]

现在我只需要查询" source" "金额" 0个数据,我试着写这个代码:

serializers.py

class SourceSerializers(serializers.ModelSerializer):
    class Meta:
        model = Source
        fields = ("id","name","amount")

class CategorySerializers(serializers.ModelSerializer):

    #Modified the following code
    source_set = SourceSerializers(Source.objects.filter(amount=0),many=True, read_only=True)

    class Meta:
        model = Category
        fields = ("id","name","amount","source")

修改了以下代码:

source_set = SourceSerializers(many=True, read_only=True)

source_set = SourceSerializers(Source.objects.filter(amount=0),many=True, read_only=True)

但结果是一样的,我希望结果是:

[
    {
        "id": 1,
        "name": "study",
        "amount": "0",
        "source": [
            {
                "id": 34,
                "name": "java",
                "amount": "0"
            },
            {
                "id": 35,
                "name": "python",
                "amount": "0"
            }
        ]
    }
]

提前致谢。

2 个答案:

答案 0 :(得分:1)

稍微更改序列化程序。您可以拥有一个SourceWithCategorySerializer来序列化相关的Category对象。然后,您可以根据金额查询Source对象,并将该QuerySet传递给序列化程序。

您的观点:

class CategoryListView(APIView):
    def get(self, request):
        sources = Source.objects.filter(amount=0)
        serializers = SourceWithCategorySerializers(sources, many=True)
        return Response(serializers.data)

序列化器:

class SourceWithCategorySerializers(serializers.ModelSerializer):
    category = CategorySerializer(read_only=True)

    class Meta:
        model = Source
        fields = ("id","name","amount", "category")

class CategorySerializers(serializers.ModelSerializer):
    class Meta:
        model = Category
        fields = ("id","name","amount")

答案 1 :(得分:1)

您可以使用SerializerMethodField

class CategorySerializer(serializers.ModelSerializer):
    source_set = serializers.SerializerMethodField('get_sources')

    def get_sources(self, category):
        sources = category.source_set.filter(amount=0)
        return SourceSerializer(instance=sources, many=True).data

    class Meta:
        model = Category
        fields = ("id", "name", "amount", "source")

我删除了复数'从你的班级名称,因为他们给我一个痒;)