我有两个模型,如下所示:
class Subject(models.Model):
subject_code = models.CharField(max_length=12, unique=True)
name = models.CharField(max_length=100)
dept_code = models.CharField(max_length=6)
和...
class Subject_assessment(models.Model):
subject_code = models.ForeignKey(Subject, related_name='sub_assessments')
year = models.CharField(max_length=4)
name = models.CharField(max_length=50)
我已经创建了序列化,当我检索主题时,我还检索与该主题相关的评估。我使用以下序列化程序来完成此任务:
class AssessmentsSerializer(serializers.ModelSerializer):
class Meta:
model = Subject_assessment
fields = (
"subject_code", "year", "name"
)
class SubjectSerializer(serializers.ModelSerializer):
sub_assessments = AssessmentsSerializer(many=True)
class Meta:
model = Subject
fields = (
"subject_code", "name", "dept_code",
"sub_assessments"
)
这段代码完全符合预期,因为它给我一个这样的结果:
{
"subject_code":"ECR2243",
"name":"Statistics",
"dept_code":"Stats",
"sub_assessments":[
{
"subject_code":"ECR2243",
"year":"2017",
"name":"Test 1"
},
{
"subject_code":"ECR2243",
"year":"2016",
"name":"Test 1"
}
]
}
我的问题是我希望只检索特定年份的评估。例如,如果我通过 2017 作为感兴趣的年份,我不希望像我目前所获得的那样检索 2016 的评估。
任何人都可以协助我如何构建我的代码以实现这一目标。提前谢谢。
修改1 我的views.py如下:
class SubjectViewSet(viewsets.ModelViewSet):
serializer_class = SubjectSerializer
lookup_field = 'subject_code'
def get_queryset(self):
qry_subject_code = self.request.GET.get('subject_code')
retrieved_sub = Subject.objects.filter(subject_code=qry_subject_code)
return retrieved_sub
答案 0 :(得分:3)
这是解决这个问题的解决方案:
class FilteredAssessmentsSerializer(serializers.ListSerializer):
def to_representation(self,data):
qry_year = self.context['request'].GET.get('year')
data = data.filter(year=qry_year)
return super(FilteredAssessmentsSerializer, self).to_representation(data)
class AssessmentsSerializer(serializers.ModelSerializer):
class Meta:
model = Subject_assessment
list_serializer_class = FilteredAssessmentsSerializer
fields = '__all__'
class SubjectSerializer(serializers.ModelSerializer):
sub_assessments = AssessmentsSerializer(many=True)
class Meta:
model = Subject
fields = (
"subject_code", "name", "dept_code",
"faculty_code", "university_code", "description",
"sub_assessments"
)
参考:我结合以下解决方案,提出了一个适合我的解决方案。
How can I apply a filter to a nested resource in Django REST framework?
答案 1 :(得分:0)
您可以尝试使用此查询:
retrieved_sub = Subject_assessment.objects.filter(subject_code__in=Subject.objects.filter(subject_code=qry_subject_code),year='2014').all()