Question

def main():
    for sayi in range(1,100):
        if not sayi%2==0:
            sonuc=hesapla(sayi)
            print(sonuc)

def hesapla(sayi):
    carpim = 1
    if carpim == 1:
        carpim=carpim*sayi
        return carpim
main()

它没有用，我想要打印：

1
3
15
105
945
10395
135135
2027025
34459425
654729075
13749310575
316234143225
.................

但它正在打印：

1
3
5
7
9
11
13
15
17
19
21
...............

Answer 1

您只能在一个功能中执行此操作。见下文。

def main():
    sonuc = 1
    for sayi in range(1,100):
        if not sayi%2==0:
            sonuc=sonuc*sayi
            print(sonuc)
main()

这样做的两种功能方式如下：

def main():
    sonuc=1
    for sayi in range(1,100):
        if not sayi%2==0:
            sonuc=hesapla(sonuc,sayi)
            print(sonuc)

def hesapla(sonuc,sayi):
   carpim=sonuc*sayi
   return carpim

main()

编辑以下是使用步骤的简化方法，而不是使用i％2检查：

def main():
    sonuc=1
    for sayi in range(1,100,2):
        sonuc=hesapla(sonuc,sayi)
        print(sonuc)

def hesapla(sonuc,sayi):
   return sonuc*sayi

main()

Answer 2

您需要保留正在运行的产品，而不是每次都重新计算它。

x = 1
for i in range(1, 100, 2):
    x *= i
    print(x)

编辑：

你真的不需要两个功能来做到这一点。这是浪费资源而且不必要的复杂。我会假设有人让你这样做

def main():
    for i in range(1, 100, 2):
        print(calculate(i))

def calculate(i):
    x = 1
    for n in range(1, i+1, 2):
        x *= n
    return x

Python 1-100将数字与函数相乘

2 个答案: