如果当天是星期一(或者d等于2),我试图使用案例选择,并且'否则'会每隔一天处理一次。
Select to_char (sysdate, 'D') d from dual,
/*if 2 or Monday then run this part*/
CASE
2
Then
SELECT DISTINCT RPAD(CLAIM.CLAIM_NUMBER, 20) ||
LPAD(CLAIM.CLAIM_ID, 15, '0') ||
TO_CHAR(CLAIM.INCIDENT_DATE, 'MMDDYYYY') ||
LPAD(' ',2) ||
'D'
FROM CLAIM,CLAIMANT,INSURER,POLICY
WHERE CLAIM.CLAIM_ID = CLAIMANT.CLAIM_ID
AND POLICY.INSURER_NUMBER = INSURER.INSURER_NUMBER
AND INSURER.INSURER_NUMBER NOT IN ('7','8')
AND CLAIMANT.EXAMINER1_CODE NOT IN ('MAYCONV')
AND CLAIM.INSURANCE_TYPE = 2
AND CLAIM.JURISDICTION_CODE <> 1
AND CLAIMANT.CLAIMANT_TYPE_CODE in (4,7)
/*if Monday then go 2 days back*/
AND CLAIMANT.EDIT_DATE > (SYSDATE - 2)
/*if not equal to 2 or any day but Monday then run this part*/
Else
SELECT DISTINCT RPAD(CLAIM.CLAIM_NUMBER, 20) ||
LPAD(CLAIM.CLAIM_ID, 15, '0') ||
TO_CHAR(CLAIM.INCIDENT_DATE, 'MMDDYYYY') ||
LPAD(' ',2) ||
'D'
FROM CLAIM,CLAIMANT,INSURER,POLICY
WHERE CLAIM.CLAIM_ID = CLAIMANT.CLAIM_ID
AND POLICY.INSURER_NUMBER = INSURER.INSURER_NUMBER
AND INSURER.INSURER_NUMBER NOT IN ('7','8')
AND CLAIMANT.EXAMINER1_CODE NOT IN ('MAYCONV')
AND CLAIM.INSURANCE_TYPE = 2
AND CLAIM.JURISDICTION_CODE <> 1
AND CLAIMANT.CLAIMANT_TYPE_CODE in (4,7)
/*if not Monday then go 1 day back*/
AND CLAIMANT.EDIT_DATE > (SYSDATE - 1)
/
答案 0 :(得分:1)
我没有密切关注您的代码,但您似乎只希望where
子句中的最后一个条件取决于一周中的某一天。
如果是这样,你需要类似的东西(警告:我没有检查代码中的任何其他内容以确保它是正确或有效的!) - 唯一的变化是在最后一行。您不需要select... from dual
,只需要编写一次select
语句。
SELECT DISTINCT RPAD(CLAIM.CLAIM_NUMBER, 20) ||
LPAD(CLAIM.CLAIM_ID, 15, '0') ||
TO_CHAR(CLAIM.INCIDENT_DATE, 'MMDDYYYY') ||
LPAD(' ',2) ||
'D'
FROM CLAIM,CLAIMANT,INSURER,POLICY
WHERE CLAIM.CLAIM_ID = CLAIMANT.CLAIM_ID
AND POLICY.INSURER_NUMBER = INSURER.INSURER_NUMBER
............
AND CLAIMANT.EDIT_DATE > SYSDATE - case to_char(sysdate, 'd') when 2 then 2 else 1 end