Question

我已经在Adobe Animate CC上创建了一个网站，我使用此代码片段完成了鼠标关注：

    this.stage.canvas.style.cursor = "none";
    this.mouseEnabled = true;
    this.addEventListener("tick", fl_CustomMouseCursor.bind(this));

function fl_CustomMouseCursor() {
    this.plus_mc.x = stage.mouseX;
    this.plus_mc.y = stage.mouseY;
    this.black_plus_mc.x = stage.mouseX;
    this.black_plus_mc.y = stage.mouseY;
}

当我在发布设置中检查它是否响应时，跟随者没有与鼠标光标对齐，只有当我将光标定位在浏览器左上角时它才会对齐，然后当我移动光标时它会走远。

Answer 1

我在ClayUUID发现了Adobe论坛的解决方案：

我将坐标分为stage.scaleX和scaleY。

这是正确的代码，使页面响应与光标跟随器对齐：

this.stage.canvas.style.cursor = "none";
this.mouseEnabled = true;
this.addEventListener("tick", fl_CustomMouseCursor.bind(this));

function fl_CustomMouseCursor() {
    this.plus_mc.x = stage.mouseX / stage.scaleX;
    this.plus_mc.y = stage.mouseY / stage.scaleY;
    this.black_plus_mc.x = stage.mouseX / stage.scaleX;
    this.black_plus_mc.y = stage.mouseY / stage.scaleY;
}

谢谢

Adobe Animate CC JavaScript：当响应处于活动状态时，鼠标跟随器未对齐

1 个答案: