我有以下三个SQL表（在MySQL中）：
Users
+---------+------+
| user_id | name |
+---------+------+
| user_1 | John |
+---------+------+
| user_2 | Jane |
+---------+------+
Places
+-----------+----------+
| places_id | name |
+-----------+----------+
| places_1 | KFC |
+-----------+----------+
| places_2 | Starbuck |
+-----------+----------+
| places_3 | Subway |
+-----------+----------+
UserLikes
+---------+-----------+----------+
| user_id | places_id | liked |
+---------+-----------+----------+
| user_1 | places_1 | yes |
+---------+-----------+----------+
| user_1 | places_2 | no |
+---------+-----------+----------+
| user_2 | places_1 | yes |
+---------+-----------+----------+
这是我用来获取user_1不喜欢或不喜欢的地方的查询。
SELECT * FROM Places WHERE places_id NOT IN（SELECT places_id FROM UserLikes WHERE user_id ='user_1'）
我需要一个与上面的查询等效的Firebase查询。你会如何在Firebase中执行此逻辑？
感谢。