{{1}}
似乎无法使其正常工作
答案 0 :(得分:2)
试
XPath
答案 1 :(得分:0)
试试这个解决方案
select sum(total1+total2) as total from balance WHERE id=( SELECT max(id) FROM balance)
答案 2 :(得分:0)
选择((从余额中选择总和(total1))+(从余额中选择sum(total2)WHERE id =(SELECT max(id)FROM balance)))为totalSums