Question

我收到错误，找不到页面。在profile.html中，我写了

export default class TestComp extends Component {

    constructor(props) {
        super(props);
        this.state = {
            viewPermission : true,
            createPermission] : true,
            editPermission]   : true,
            deletePermission] : true

        };
    }
 // Rest of your component methods such as render and others

在这部分

 <!DOCTYPE html>

  <html lang="ja">
    <head>
      <meta charset="utf-8">
      <meta http-equiv="X-UA-Compatible" content="IE=edge">
      <meta name="viewport" content="width=device-width, initial-scale=1">
      <title>UPLOAD</title>
    </head>
    <body>
    <form action="registration/accounts/fashion_result.html">
      <input type="submit" value="ResultShow">
    </form>

    <div class="container">
      <form action="{% url 'accounts:upload_save' %}" method="POST" enctype="multipart/form-data">
        {% csrf_token %}
        <input type="file" name="files[]" multiple>
        <input type="hidden" value="{{ p_id }}" name="p_id">
        <input type="submit" value="Upload">
      </form>
    </div>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
    </body>
  </html>

我想进行屏幕转换（如果我按下此按钮，我想在浏览器中看到fashion_result.html。

但现在，我收到了错误。我该如何解决这个问题？

此外，我加入了urls.py

<form action="registration/accounts/fashion_result.html">
          <input type="submit" value="ResultShow">
 </form>

profile.html中的

from django.conf.urls import patterns, url
from django.views.generic import TemplateView

urlpatterns = patterns('',
    url(r'^/fashionresults/$', TemplateView.as_view(template_name='registration/accounts/fashion_result.html'), name='fashionresults'

)

（在目录中，有fashion_result.html）

Answer 1

用户模板View解决此问题

from django.conf.urls import patterns, url
from django.views.generic import TemplateView

urlpatterns = patterns('',
    url(r'^/test/$', TemplateView.as_view(template_name='todo/index.html'), name="test"),
)

在html页面

<a href="{% url 'test' %}" >ResultShow</a>

Answer 2

这对你有用： -

模板 -

<form action="/fashion_result">
          <input type="submit" value="ResultShow">
 </form>

urls.py： -

from django.conf.urls import url,include
from webpage import views
# from django.conf import settings

urlpatterns = [
    url(r'^$',views.home),
    url(r'^fashion_result/$',views.fashionResult),

views.py -

from django.shortcuts import render
import json

def home(request):
    return render(request, 'home.html')


def fashionResult(request):
    return render(request, 'registration/accounts/fashion_result.html')

Answer 3

如果文件位于同一文件夹中，则取决于文件所在的位置

<form action="fashion_result.html">

或者做一件事＆＃34; Shift +右键单击＆＃34;然后＆＃34;复制为路径＆＃34;

回来并粘贴＆＃34;表格动作＆＃34;绝对有效。

页面未找到错误。请求网址错误了吗？

3 个答案: