Django中的URL错误，找不到页面404

Question

这是我的views.py：

from django.http import Http404 
from django.shortcuts import render
from .models import Album


def index(request):
    all_albums = Album.objects.all()
    return render(request, 'music/index.html', {'all_albums': all_albums})


def detail(request, album_id):
    try:
        album = Album.objects.get(pk=album_id)
    except Album.DoesNotExist:
        raise Http404("Album does not exist")
    return render(request, '/music/detail.html', {'album': album})

这是我的music\urls.py：

from django.conf.urls import url
from . import views

urlpatterns = (
    url(r'^$', views.index, name='index'),
    url(r'^(?P<album_id>[0-9]+)/$', views.detail, name='detail'),
)

当我运行此代码时，我收到的错误为：

Answer 1

由于stacktrace表示您尝试打开http://127.0.0.1/music/id/1页面而不是http://127.0.0.1/music/1，但urls.py中没有此类网址格式。您需要尝试打开http://127.0.0.1/music/1或添加新模式：

url(r'^id/(?P<album_id>[0-9]+)/$', views.detail, name='detail')

查看http://127.0.0.1/music/id/1页面。