我有以下查询:
SELECT
g.Gender,
a.AgeGroup,
count(*) as Count
FROM
client c
INNER JOIN AgeGroup a
ON c.age BETWEEN a.StartRange AND a.EndRange
INNER JOIN Gender G on
C.GenderID = G.GenderID
group by
g.Gender,
a.AgeGroup
order by AgeGroup, Gender
给出了以下结果:
Gender AgeGroup Count
Male <=25 4
Unknown <=25 2
Female >35 2223
Male >35 6997
Transgender >35 43
Unknown >35 2
Female 26-35 413
Male 26-35 590
Transgender 26-35 5
我需要尝试做的是将性别列转换为列标题并包含总计。
AgeGroup Male Female Trans Unknown Total
<= 25: 4 0 0 2 6
26 - 35: 590 413 5 0 1008
> 35: 6997 2223 43 2 9265
Total: 7591 2636 48 4 10279
我到目前为止:
SELECT *
FROM (
SELECT
g.Gender as [Gender],
a.AgeGroup
FROM
client c
INNER JOIN AgeGroup a
ON c.age BETWEEN a.StartRange AND a.EndRange
INNER JOIN Gender G on
C.GenderID = G.GenderID
) as s
PIVOT
(
COUNT(Gender)
FOR [Gender] IN (Male,Female,Transgender,Unknown)
)AS pvt
返回:
AgeGroup Male Female Transgender Unknown
<=25 4 0 0 2
26-35 590 413 5 0
>35 6997 2223 43 2
但我没有总数。
我有办法做到这一点吗?
答案 0 :(得分:1)
试试这个..
SELECT *,
(select sum(v)
from
(values(male),
(female),
(transgender),
(unknown))
as val(v)) as total
FROM (
SELECT
g.Gender as [Gender],
a.AgeGroup
FROM
client c
INNER JOIN AgeGroup a
ON c.age BETWEEN a.StartRange AND a.EndRange
INNER JOIN Gender G on
C.GenderID = G.GenderID
) as s
PIVOT
(
COUNT(Gender)
FOR [Gender] IN (Male,Female,Transgender,Unknown)
)AS pvt
更新要求:
我建议将整个表放入一些临时表中以获得可读性并执行此操作
所以你的上述查询会像这样
SELECT *,
(select sum(v)
from
(values(male),
(female),
(transgender),
(unknown))
as val(v)) as total
into #temp
from
rest of pivot query
然后分组总计
select
case when grouping(agegroup)=1 then 'total' else agegroup end agegroup,
sum(male) as male,
sum(female) as 'female',
sum(trans) as 'trans',
sum(unknown) as 'unknown',
sum(total) as 'Total'
from #temp
group by
grouping sets
(
(agegroup),
()
)