Question

我有一个数组：

arr = [["group1", "user1", "user2", "user3", "AD-user1", "AD-user2"],
       ["group2", "user4"]]

我想做那样的事情：

arr.each do |item|
        if (item.include? "AD-user") then
            arr_h = { "Group" => arr[1],
                      "User" => arr[number_of_element_with_AD-user_name] }
        else
        #something else
        end
end

我不知道如何定义if语句中找到的值的索引。在这种情况下，我有两个以＆＃34开头的用户名; AD-user＆＃34;字符串，但它可以是很多。组名称始终是子阵列中的第一个值。

Answer 1

试试这个：

new_ary = []
arr.each do |a|
  b = a.select{|e| e.include? "AD-user"}
  if b.empty? 
    #something else
    new_ary << {"Group" => a[0], "Users" => "AD-user not available"}
  else
    new_ary << {"Group" => a[0], "Users" => b}
  end
end

> new_ary
#=> [{"Group"=>"group1", "Users"=>["AD-user1", "AD-user2"]}, {"Group"=>"group2", "Users"=>"AD-user not available"}]

new_ary = []
arr.each do |a|
  b = a.select{|e| e.include? "AD-user"}
  new_ary << {"Group" => a[0], "Users" => b}
end

> new_ary
#=> [{"Group"=>"group1", "Users"=>["AD-user1", "AD-user2"]}, {"Group"=>"group2", "Users"=>[]}]

if语句Ruby返回的数组中的值索引

1 个答案: