不返回if语句中的值，MATLAB

Question

我正在评估数据集的准确性置信区间，并且我计算95％或99％的置信区间，但是对应于较低区间和较高区间的值未从函数返回，请指导我我到底做错了什么：

function [Accuracy,lowerInterval,upperInterval] = ConstructInterval(Ypredict, Ytest, confLevel)
n = size(Ypredict,1);
correct = Ypredict == Ytest;
Accuracy = mean(correct);
confLevel = floor(confLevel*100);
if(confLevel == 99)
    lowerInterval = Accuracy - 2.576*sqrt(Accuracy*(1-Accuracy)/n);
    upperInterval = Accuracy + 2.576*sqrt(Accuracy*(1-Accuracy)/n);
end
if(confLevel == 95)
    lowerInterval = Accuracy - 1.96*sqrt(Accuracy*(1-Accuracy)/n);
    upperInterval = Accuracy + 1.96*sqrt(Accuracy*(1-Accuracy)/n);
end
Accuracy = 100*Accuracy;
lowerInterval = lowerInterval*100;
upperInterval = upperInterval*100;
end

谢谢。

Answer 1

问题在于，当我调用函数时，我只将值保存为：

f = ConstructInterval(y(testInstanceLabel == 1),pred_linear, 0.99)

而不是

[f,g,h] = ConstructInterval(y(testInstanceLabel == 1),pred_linear, 0.99)

新秀错误。