试图将方程存储到变量中

Question

我正在试图找出如何将计算出的总工资存储到grossPay变量中，以便将其用于计算净工资。使用结构时，我会抛弃它。

#include<string>
#include <iostream>
using namespace std;

struct Workers {
    string name;
    double hourlyWage;
    int hoursWorkedPerDay;
    int hoursWorkedPerWeek;

};
int healthTax = 130;
double otherTaxes = 0.17;
double grossPay;

int main() {
    Workers JohnDoe;
    JohnDoe.name = "John Doe";
    JohnDoe.hourlyWage = 8.50;
    JohnDoe.hoursWorkedPerDay = 6;
    cout<<"- John Doe's weekly earnings - "<< endl;
    cout<<"Hourly rate: $8.50" << endl;
    cout<<"Hours worked per day: 6" << endl;
    cout<<"Gross pay: $" << 7 * (JohnDoe.hourlyWage * JohnDoe.hoursWorkedPerDay)<<endl; // gross pay
    grossPay; // how to store gross pay into this variable?
    cout<<"Net pay: $" << otherTaxes * (grossPay - healthTax) / 100; // net pay  
}

Answer 1

我认为您可能无法理解变量的工作原理。您不存储公式，存储计算公式的结果：

     double grossPay =  7 * (JohnDoe.hourlyWage * JohnDoe.hoursWorkedPerDay);

Answer 2

其他答案是正确的，但稍微好一点的解决方案是将Worker引用作为参数并返回结果的函数：

double getGrossPay(const Workers& worker) {
        return 7 * (worker.hourlyWage * worker.hoursWorkedPerDay);
}

然后简单地说：

cout<<"Gross pay: $" << getGrossPay(JohnDoe) <<endl; // gross pay

Answer 3

这就是你要做的事情：

double grossPay =  7 * ( JohnDoe.hourlyWage * JohnDoe.hoursWorkedPerDay );

然后您可以使用它，在这种情况下，打印它：

cout<<"Gross pay: $" << grossPay <<endl;