我有一张包含以下信息的表格
ID,DateTime,EventType
1,6/5/2013 9:35:00,B
1,6/5/2013 9:35:24,A
2,6/5/2013 9:35:36,B
3,6/5/2013 9:36:11,D
2,6/5/2013 9:39:16,A
3,6/5/2013 9:40:48,B
4,7/5/2013 9:35:19,B
4,7/5/2013 9:35:33,A
5,7/5/2013 9:35:53,B
5,7/5/2013 9:36:06,D
6,7/5/2013 9:39:39,A
7,7/5/2013 9:40:28,B
8,8/5/2013 9:35:02,A
7,8/5/2013 9:35:08,A
8,8/5/2013 9:35:29,B
6,8/5/2013 9:36:39,B
我需要计算事件每天改变状态的次数,只要状态之间的时间在这段时间内少于30秒。
基本上我正在寻找以下结果集
6/5/2013 | 1
7/5/2013 | 2
8/5/2013 | 1
我尝试了几种不同类型的查询,但没有任何效果。我正在使用SQL Server Reporting Services 2008。
答案 0 :(得分:0)
试试这个:
select CONVERT(VARCHAR(10), a.DateTime, 103) [Date], count(a.ID) Count from Table a
inner join Table b on a.ID = b.ID
where DATEDIFF(second,a.DateTime,b.DateTime) between 1 and 29 and a.ID = b.ID
and Cast(a.DateTime as Date) = Cast(b.DateTime as date)
group by CONVERT(VARCHAR(10), a.DateTime, 103)
如果有帮助,请告诉我。
答案 1 :(得分:0)
declare @t table (ID int,[DateTime] datetime ,EventType varchar);
insert @t values
(1,'6/5/2013 9:35:00','B'),
(1,'6/5/2013 9:35:24','A'),
(2,'6/5/2013 9:35:36','B'),
(3,'6/5/2013 9:36:11','D'),
(2,'6/5/2013 9:39:16','A'),
(3,'6/5/2013 9:40:48','B'),
(4,'7/5/2013 9:35:19','B'),
(4,'7/5/2013 9:35:33','A'),
(5,'7/5/2013 9:35:53','B'),
(5,'7/5/2013 9:36:06','D'),
(6,'7/5/2013 9:39:39','A'),
(7,'7/5/2013 9:40:28','B'),
(8,'8/5/2013 9:35:02','A'),
(7,'8/5/2013 9:35:08','A'),
(8,'8/5/2013 9:35:29','B'),
(6,'8/5/2013 9:36:39','B');
--select * from @t order by ID, DateTime;
with cte as (
select *, cast([DateTime] as date) the_date, row_number() over (partition by ID order by DateTime) row_num
from @t
)
select c1.the_date, count(1)
from cte c1
join cte c2
on c2.ID = c1.ID
and c2.row_num = c1.row_num + 1
where datediff(S,c1.DateTime, c2.DateTime) < 30
group by c1.the_date
order by c1.the_date;