Question

这是我的案例字符串：

"This is a test.  How many???  " + "Senteeeeeeeeeences are here... there should be 5!  Right?"

使用

String[] words = getText().split("[( +)!.?,]");

我得到这个数组： [This, is, a, test, , , How, many, , , , , Senteeeeeeeeeences, are, here, , , , there, should, be, 5, , , Right

如何取消空字符串？

Answer 1

你的问题不够明确。
如果你告诉我，那么不那么我可以更新答案或删除。

您只需要全局匹配所有非单词。那就是它。

您需要什么
[^\w]+

如何运作
对于拆分，它匹配除[a-zA-Z0-9_]之外的所有内容。

prove

快速测试

echo "This is a test.  How many???  " + "
 Senteeeeeeeeeences are here... there should 
 be 5!  Right?" | perl -lne 'print "@{[split( /[^\w]+/g )]}"'

<强>输出
This is a test How many Senteeeeeeeeeences are here there should be 5 Right

Answer 2

String stringToSearch = "This is a test.  How many???  " + "Senteeeeeeeeeences are here... there should be 5!  Right?";

Pattern p1 = Pattern.compile("[\\W]+");
String[] str = p1.split(stringToSearch);
System.out.println(Arrays.asList(str));

输出：

[这，是，a，测试，如何，很多，Senteeeeeeeeeences，是，在这里，那里，应该，是，5，对]

java正则表达式在字符串中查找单词在符号中找到空字符串，如。，！（？和空格

2 个答案:

prove