Question

我的正则表达式必须解析多行字符串中超过6个符号的所有单词。

        Pattern pattern = Pattern.compile("(\\w{7,}\\s\\b.*)");

        Matcher mm = pattern.matcher(lines);

        if (mm.matches()) {

            String oldGroup = mm.group();

________以下是示例输入：

1234567 1234567 1234567
1234 123 1234567
123 12345 1234 1234567
123

_______这是预期的输出：

1234567 1234567 1234567 1234567 1234567

所以，我只需要输出带有6个或更多字母符号的单词。

Answer 1

(\b\S{7,}\b)/

1st Capturing group (\b\S{7,}\b)
    \b assert position at a word boundary (^\w|\w$|\W\w|\w\W)
    \S{7,} match any non-white space character [^\r\n\t\f ]
        Quantifier: {7,} Between 7 and unlimited times, as many times as possible, giving back as needed [greedy]
    \b assert position at a word boundary (^\w|\w$|\W\w|\w\W)

正则表达式在字符串中查找长度为6或更长的所有单词

1 个答案: