Question

我真的想问一下sql server中的数据透视表。我试图做一些查询结构是这样的。

DECLARE @cols AS NVARCHAR(MAX) 
DECLARE @query  AS NVARCHAR(MAX)
DECLARE @tanggal_awal date
DECLARE @tanggal_akhir date
DECLARE @print nvarchar(MAX)

CREATE TABLE #datatable  
(
    product_id int,
    product_date date,
    product_ammount int
)

SET @tanggal_awal = convert(date,'02-01-2017')
SET @tanggal_akhir = convert(date,'02-27-2017')



insert into #datatable (product_id,product_date,product_ammount) VALUES 
            (1,getdate(),100),
            (1,getdate(),900),
            (2,dateadd(DD,-1,getdate()),400),
            (3,DATEADD(DD,4,getdate()),300),
            (1,dateadd(DD,4,getdate()),200),
            (2,dateadd(DD,2,getdate()),700),
            (4,dateadd(DD,-3,getdate()),1000)

--SELECT * FROM @datatable

;WITH CTE (datelist,maxdate) AS 
(
    select min(@tanggal_awal) datelist, max(product_date) maxdate
    from #datatable
    union all
    select dateadd(dd, 1, datelist), @tanggal_akhir
    from cte
    where datelist < maxdate
) SELECT c.datelist 
    into #temp
    from cte c

select @cols =  STUFF((SELECT distinct ',' + QUOTENAME(convert(CHAR(10), datelist, 120)) 
                from #temp
                FOR XML PATH(''), TYPE
                ).value('.', 'NVARCHAR(MAX)') 
                ,1,1,'')

--SELECT d.datelist, b.product_id, SUM(b.product_ammount) 
--  FROM #temp d left join #datatable b on 
--  d.datelist between @tanggal_awal and @tanggal_akhir
--  AND d.datelist = b.product_date
--  GROUP BY b.product_id, d.datelist

--select b.product_id, d.datelist, 
--                sum(b.product_ammount) PivotDate
--                from #datatable b
--                left join #temp d
--                on d.datelist between @tanggal_awal and @tanggal_akhir
--              and d.datelist = b.product_date
--group by b.product_id, d.datelist
--order by b.product_id


SET @query = 'SELECT product_id, '+@cols+' FROM 
             (
                select b.product_id, d.datelist, convert(CHAR(10), datelist, 120) PivotDate
                from #datatable b
                left join #temp d
                on d.datelist between @tanggal_awal and @tanggal_akhir
                and d.datelist = b.product_date

            ) x
            pivot 
            (
                count(datelist)
                for PivotDate in (' +@cols+ ')
            ) p'


EXECUTE sp_executesql @query ,N'@tanggal_awal DATE, @tanggal_akhir DATE', @tanggal_awal,@tanggal_akhir
GO
drop table #temp
go
drop table #datatable

此查询的结果主要是＆product;＆lt; product_id＆＃39;在各自的日期。但是，我想要像这样得到基于product_ammount的总和。

-------------------------------------
|product_id| 2017-01-02 | 2017-02-02|
-------------------------------------
|1         | 0          | 1000      |
-------------------------------------
|2         | 900        | 0         |
-------------------------------------
|3         | 700        | 0         |
-------------------------------------

任何人都可以给我最好的方法来处理连接和聚合，特别是对于这种情况吗？非常感谢你。

- 更新在Shakeer Mirza的查询之后，结果是这样的。

我们可以分组吗？

Answer 1

请尝试以下方法。我认为您需要将您的Pivot更改为SUM的{{1}}和qry product_ammount以便选择<{p>}中的X

product_ammount

<强>更新替换Null

SET @query = 'SELECT product_id, '+@cols+' FROM 
             (

                select b.product_id,  convert(CHAR(10), datelist, 120) PivotDate,  product_ammount  
                from #datatable b
                left join #temp d
                on d.datelist between  @tanggal_awal and @tanggal_akhir
                and d.datelist = b.product_date


            ) x
            pivot 
            (
                sum(product_ammount)
                for PivotDate in (' +@cols+ ')
            ) p'


EXECUTE sp_executesql @query ,N'@tanggal_awal DATE, @tanggal_akhir DATE', @tanggal_awal,@tanggal_akhir
GO
drop table #temp
go
drop table #datatable

在Select of yourquery中替换上面的@COLS_ISNULL。

DECLARE @COLS_ISNULL VARCHAR(MAX)='';

SELECT @COLS_ISNULL = @COLS_ISNULL +COLS_ISNULL+',' FROM (
SELECT distinct   'ISNULL('+QUOTENAME(convert(CHAR(10), datelist, 120))+',0) 'as COLS_ISNULL
                from #temp)A
--to remove last comma.
SELECT @COLS_ISNULL = SUBSTRING (@COLS_ISNULL,1,LEN(@COLS_ISNULL)-1)

来自评论：

这是我SSMS的输出

Answer 2

您的查询可以简化为：

SET @query = 
    'SELECT product_id, '+@cols+' FROM 
     (
         select b.product_id, b.product_ammount, 
                convert(CHAR(10), product_date, 120) PivotDate
         from #datatable b
         where product_date between @tanggal_awal and @tanggal_akhir                   
     ) x
     pivot 
     (
         sum(product_ammount)
         for PivotDate in (' +@cols+ ')
     ) p'

您不必LEFT JOIN到#temp，因为for操作中的pivot子句确实返回了所有日期的列表。

Answer 3

基于Shakeer Mirza和Giorgos Betos回答这个问题，最后我解决了这个问题。这是此问题的完整查询

DECLARE @cols AS NVARCHAR(MAX)
DECLARE @colswithNoNulls AS NVARCHAR(MAX)
DECLARE @query  AS NVARCHAR(MAX)
DECLARE @tanggal_awal date
DECLARE @tanggal_akhir date
DECLARE @print nvarchar(MAX)

CREATE TABLE #datatable  
(
    product_id int,
    product_date date,
    product_ammount int
)

SET @tanggal_awal = convert(date,'02-01-2017')
SET @tanggal_akhir = convert(date,'02-27-2017')



insert into #datatable (product_id,product_date,product_ammount) VALUES 
            (1,getdate(),100),
            (1,getdate(),900),
            (2,dateadd(DD,-1,getdate()),400),
            (3,DATEADD(DD,4,getdate()),300),
            (1,dateadd(DD,4,getdate()),200),
            (2,dateadd(DD,2,getdate()),700),
            (4,dateadd(DD,-3,getdate()),1000)


;WITH CTE (datelist,maxdate) AS 
(
    select min(@tanggal_awal) datelist, max(product_date) maxdate
    from #datatable
    union all
    select dateadd(dd, 1, datelist), @tanggal_akhir
    from cte
    where datelist < maxdate
) SELECT c.datelist 
    into #temp
    from cte c

select @cols =  STUFF((SELECT distinct ',' + QUOTENAME(convert(CHAR(10), datelist, 120)) 
                from #temp
                FOR XML PATH(''), TYPE
                ).value('.', 'NVARCHAR(MAX)') 
                ,1,1,'')

select @colswithNoNulls =   STUFF((SELECT distinct ',ISNULL(' + QUOTENAME(convert(CHAR(10), datelist, 120)) +',''0'') '+ QUOTENAME(convert(CHAR(10), datelist, 120)) 
                            from #temp
                            FOR XML PATH(''), TYPE
                            ).value('.', 'NVARCHAR(MAX)') 
                            ,1,1,'')

SET @query = 
            'SELECT product_id, '+ @colswithNoNulls+' FROM 
             (
                select b.product_id, coalesce(b.product_ammount,0) as product_ammount, 
                       convert(CHAR(10), product_date, 120) PivotDate
                from #datatable b
                where product_date between @tanggal_awal and @tanggal_akhir                                
            ) x
            pivot 
            (
                sum(product_ammount)
                for PivotDate in (' +@cols+ ')
            ) p'            


EXECUTE sp_executesql @query ,N'@tanggal_awal DATE, @tanggal_akhir DATE', @tanggal_awal,@tanggal_akhir
GO
drop table #temp
go
drop table #datatable

这个想法来自How to replace (null) values with 0 output in PIVOT。这个想法本身就是制作两个不同的cols，一个用于cols，另一个用于ISNULL。希望这个问题能在不久的将来解决很多问题:)

基于日期之间的数据透视表求和

3 个答案: