Question

这就是我的......

[{
  "programName": "Testing 102",
  "recommendedComparisons": [{
    "programName": "Testing 101",
    "id": 2
  }, {
    "programName": "Testing 401",
    "id": 4
  }],
  "id": 1,
  "programId": 3
}, {
  "programName": "Testing 101",
  "recommendedComparisons": [{
    "programName": "Testing 102",
    "id": 3
  }],
  "id": 9,
  "programId": 2
}]

我想要的是两个推荐比较列表。

Testing 101, Testing 401和Testing 102

我确定必须有简单的方法。

Answer 1

var data = [{
  "programName": "Testing 102",
  "recommendedComparisons": [{
    "programName": "Testing 101",
    "id": 2
  }, {
    "programName": "Testing 401",
    "id": 4
  }],
  "id": 1,
  "programId": 3
}, {
  "programName": "Testing 101",
  "recommendedComparisons": [{
    "programName": "Testing 102",
    "id": 3
  }],
  "id": 9,
  "programId": 2
}];

var result = data.map(function(item) {
    return item.recommendedComparisons.map(function(comp) {
        return comp.programName;
    });
});

Answer 2

您要找的是数组对象的地图功能。

您正在寻找推荐比较的程序名称。为此，你需要1个map函数来进行比较，然后你需要再次调用map，并在子函数中调用map来返回程序名称。

由于您提到了逗号分隔列表，最好不要返回数组本身。而是创建一个新字符串，并用逗号连接子数组，并用新行附加它。

我相信这就是你要找的东西

＆＃13;

var array = [{"programName":"Testing 102","recommendedComparisons":[{"programName":"Testing 101","id":2},{"programName":"Testing 401","id":4}],"id":1,"programId":3},{"programName":"Testing 101","recommendedComparisons":[{"programName":"Testing 102","id":3}],"id":9,"programId":2}]

var results = array.map(function(a) { return a.recommendedComparisons
  }).map(function(b) {
      return b.map(function(c) {
          return c.programName;
      });
  });

var str = "";

for (var i = 0; i < results.length; i++) {
    str += results[i].join(',') + "\n"
}

console.log(str);

＆＃13;

Answer 3

利用map函数可以转换对象。

var recommendedComparisons = data.map(x => x.recommendedComparisons.map(x=>x.programName));
使用Destructuring获取2个结果列表。

var [firstList,secondList] = recommendedComparisons;

＆＃13;

var data = [{
  "programName": "Testing 102",
  "recommendedComparisons": [{
    "programName": "Testing 101",
    "id": 2
  }, {
    "programName": "Testing 401",
    "id": 4
  }],
  "id": 1,
  "programId": 3
}, {
  "programName": "Testing 101",
  "recommendedComparisons": [{
    "programName": "Testing 102",
    "id": 3
  }],
  "id": 9,
  "programId": 2
}];

var recommendedComparisons = data.map(x => x.recommendedComparisons.map(x=>x.programName));

var [firstList,secondList] = recommendedComparisons;
console.log(firstList);
console.log(secondList);

＆＃13;

Answer 4

我还没有测试过，但我很确定这是对的。我现在要测试一下。

const list = [
  {
    "programName":"Testing 102",
    "recommendedComparisons":[
      { "programName": "Testing 101", "id":2 },
      { "programName": "Testing 401", "id":4 }
    ],
    "id":1,
    "programId":3
  },
  {
    "programName":"Testing 101",
    "recommendedComparisons":[
       {"programName":"Testing 102","id":3}
    ],
    "id":9,
    "programId":2
  }
];

let listOfComparisonLists = [];

list.map((program) => {
  const programNames = program.recommendedComparisons.map((comp) => comp.programName);

  listOfComparisonLists.push(programNames);
});

console.log(listOfComparisonLists); // [['Testing 104', 'Testing 401'],['Testing 102']]

使用javascript将嵌套的json放入以逗号分隔的列表中

4 个答案: