Question

我从一行获取数据是一堆整数，我需要用逗号分隔它们以将它们用于chart.js数据集数据。所以我在这里有阵列：

if (mysqli_num_rows($result) > 0) {

  $categories = [];
  while($row = mysqli_fetch_assoc($result)) {
    $categories[] = $row;     
  }

echo json_encode($categories);

我需要把它变成json编码的字符串：

我的阵列回声为：

[{"respondent_sdo":"2","respondent_dcto":"3","respondent_ed":"5","respondent_ca":"5","respondent_dhpt":"3","respondent_irt":"6","respondent_gl":"2","respondent_il":"5"}]

我需要将上面的内容输出为2,3,5,5,3,6,5

var dataString= "<?php echo json_encode($categories, JSON_NUMERIC_CHECK);  ?>";
var catData = JSON.parse(dataString);


    var ctx = document.getElementById("myChart1");
    var myChart1 = new Chart(ctx, {
      type: 'radar',
        options: {
             legend: {
                display: true
             },
             tooltips: {
                enabled: false
             },
            scale: {
                ticks: {
                    beginAtZero: true,
                    stepSize: 1
                }
            }         
        },  
      data: {
        labels: ["Strategic Development and Ownership", 
                 "Driving change through others", 
                 "Exec Acumen", 
                 "Commercial Acumen", 
                 "Develops High Performance Teams", 
                 "Innovation and risk taking", 
                 "Global Leadership", 
                 "Industry Leader"
                 ],


        datasets: [{
          label: 'Ian Galbraith',
          backgroundColor: "rgba(255,6255,255,0)",
          borderColor: "lightblue",
          data: catData,
        }]
      }
    });

Answer 1

为什么不在PHP文件中将关联数组更改为数字数组，如：

而不是：

if (mysqli_num_rows($result) > 0) {

  $categories = [];
  while($row = mysqli_fetch_assoc($result)) {
    $categories[] = $row;     
  }

echo json_encode($categories);

使用：

if (mysqli_num_rows($result) > 0) {

  $categories = [];
  while($row = mysqli_fetch_assoc($result)) {
    $categories[] = $row;     
  }
$response = array();
foreach($categories as $c){
   foreach($c as $val){
      $response[] = (int)$val;
   }
}
echo json_encode($response);

我希望它有所帮助

Answer 2

要实现此目的，您可以使用Object.keys从对象获取密钥，然后使用这些密钥中的值填充数组：

＆＃13;

// Use this in production
//var arr = <?php echo json_encode($categories, JSON_NUMERIC_CHECK);  ?>;

// For this example:
var arr = [{
  "respondent_sdo": "2",
  "respondent_dcto": "3",
  "respondent_ed": "5",
  "respondent_ca": "5",
  "respondent_dhpt": "3",
  "respondent_irt": "6",
  "respondent_gl": "2",
  "respondent_il": "5"
}]

var catData = [];
Object.keys(arr[0]).forEach(function(key) {
  catData.push(parseInt(arr[0][key], 10));
});

console.log(catData);

＆＃13;

但是，我建议您改为执行逻辑来提取PHP代码中的整数，并将它们提供给JS。

Answer 3

或者使用数组映射函数。

var catData = JSON.parse(dataString);
var values ='';
values += catData.map(function(a) {
    return a.foo+',';
});

values = values.replace(/,\s*$/, ""); //to remove last coma

将php数组转换为逗号分隔数组

3 个答案: