复杂的SQL查询 - 计数+拥有+组 - 如何修复查询

Question

我正在寻找sql中一个相当复杂的查询的帮助。

查询应该听起来像:(首先查询下面） 我正在寻找类型的产品：床和我想显示分配给他们的所有选项 - 将它们分组并计算它们中有多少。 （如下图所示）。

查询的第二部分:(下面的第二个查询） 当用户单击复选框时，我希望仅显示和计算已检查选项的产品，并计算这些产品的数量。 （这是问题）

首先查询：

SELECT COUNT(DISTINCT id_product) as productMatched, COUNT(id_product) as haveProducts, product_to_features.id_feature_value, product_to_features.id_feature, feature_value_langs.name,feature_value_langs.id_feature_value, products.active 
FROM product_to_features 
LEFT JOIN feature_value_langs 
   ON product_to_features.id_feature_value = feature_value_langs.id_feature_value 
LEFT JOIN products 
   ON product_to_features.id_product = products.id 
WHERE price_retail >= 655.00 
   AND price_retail <= 6455.00 
   AND height >= 0.0 AND height <= 120.0 
   AND width >= 0.0 AND width <= 262.0 
   AND depth >= 0.0 AND depth <= 276.0 
   AND product_to_features.id_feature_value IN (15981,15982,15983,16011,16012,16013,16019)  //its shows ids of bed sizes
   AND products.active = 1 
GROUP BY product_to_features.id_feature_value

这表明：

第二个查询 - 不能正常工作：

SELECT COUNT(DISTINCT product_to_features.id_feature_value) as productMatched, COUNT(product_to_features.id_product) as haveProducts, product_to_features.id_feature_value, product_to_features.id_feature, id_product as ProductId, feature_value_langs.name, products.active 
FROM product_to_features 
LEFT JOIN feature_value_langs 
   ON product_to_features.id_feature_value = feature_value_langs.id_feature_value 
LEFT JOIN products 
   ON product_to_features.id_product = products.id 
WHERE price_retail >= 655 AND price_retail <= 6455 
   AND height >= 0 AND height <= 120 
   AND width >= 0 AND width <= 262 
   AND depth >= 0 AND depth <= 276 
   AND (product_to_features.id_feature_value IN (15981,15982,15983,16011,16012,16013,16019)  // (its first checkbox group where non is checked - so i send all values )
   OR product_to_features.id_feature_value IN ( 1096)  // 1096 - its checked option from second checkbox group)
   OR product_to_features.id_feature_value = 1483 )   // 1483 - is BED TYPE (must be)
  AND products.active = 1 
GROUP BY product_to_features.id_product having productMatched>2 
ORDER BY product_to_features.id_feature

例如，如果我检查80x200，它必须刷新所有其他复选框并显示匹配当前选项（已选中）和计数匹配产品的数量。

这是我的数据库结构：

DESCRIBE product_to_features

id  int(11) NO  PRI     auto_increment  
id_feature  int(10) unsigned    NO  MUL         
id_product  int(10) unsigned    NO  MUL         
id_feature_value    int(10) unsigned    NO  MUL     


desc `feature_value_langs`

id  int(11) NO  PRI     auto_increment  
id_feature_value    int(10) unsigned    NO  MUL         
id_lang int(10) unsigned    NO  MUL         
name    varchar(255)    YES MUL