Question

STATUS  DATE    MARKET  COUNTRY ACC INCT    VOL  TOTAL
INC 7/2/2018    CHICAGO US  123456  AB  3   0.06 
DEL 7/3/2018    CHICAGO US  123456  AB  3   0.06  
INC 7/3/2018    CHICAGO US  67890   AB  3   0.06 
INC 7/6/2018    CHICAGO US  700000  CBO     25  0.5 
INC 7/11/2018   EUROPE  WG  253235  EFDX    1   0.02
INC 7/18/2018   NEWYORK US  700000  RTY     2   0.04 
INC 7/24/2018   CHICAGO US  700000  CBO     2   0.04 
INC 7/25/2018   EUROPE  WG  253235  EFDX    1   0.02

在（inc，del）下，如果我发现MARKET，COUNTRY，ACC，INCT，VOL，TOTAL相同，那么我只需要取第三条记录就消除前两个记录 INC 7/3/2018芝加哥美国67890 AB 3 0.06

我的预期输出是

STATUS  DATE    MARKET  COUNTRY ACC INCT    VOL  TOTAL <br>
INC 7/3/2018    CHICAGO US  67890   AB  3   0.06 <br>
INC 7/6/2018    CHICAGO US  700000  CBO     25  0.5<br>
INC 7/11/2018   EUROPE  WG  253235  EFDX    1   0.02<br>
INC 7/18/2018   NEWYORK US  700000  RTY     2   0.04<br>
INC 7/24/2018   CHICAGO US  700000  CBO     2   0.04<br>
INC 7/25/2018   EUROPE  WG  253235  EFDX    1   0.02<br>

我只需要在SQL Server和Oracle中的SQL中执行此操作。我将不胜感激。非常感谢。

Answer 1

使用公用表表达式（CTE）找出哪些行具有偏移的“ INC”和“ DEL”记录。然后，从该CTE中选择并排除那些。像这样：

WITH tmp as ( 
SELECT id.*, 
       sum(decode(status,'INC',total,'DEL',-total)) 
           over ( partition by market, country, acc, inct, vol, total) incdel 
FROM input_data id )
SELECT status, trx_date, market, country, acc, inct, vol, total
FROM   tmp 
WHERE incdel != 0;

这是一个完整的示例，其中包含测试数据：

with input_data (STATUS,  TRX_DATE,    MARKET,  COUNTRY, ACC, INCT,    VOL,  TOTAL ) AS (
SELECT 'INC', TO_DATE('7/2/2018','MM/DD/YYYY'),    'CHICAGO', 'US',  123456,  'AB',  3,   0.06 FROM DUAL UNION ALL
SELECT 'DEL', TO_DATE('7/3/2018','MM/DD/YYYY'),    'CHICAGO', 'US',  123456,  'AB',  3,   0.06 FROM DUAL UNION ALL  
SELECT 'INC', TO_DATE('7/3/2018','MM/DD/YYYY'),    'CHICAGO', 'US',  67890,   'AB',  3,   0.06  FROM DUAL UNION ALL
SELECT 'INC', TO_DATE('7/6/2018','MM/DD/YYYY'),    'CHICAGO', 'US',  700000,  'CBO',     25,  0.5  FROM DUAL UNION ALL
SELECT 'INC', TO_DATE('7/11/2018','MM/DD/YYYY'),   'EUROPE',  'WG',  253235,  'EFDX',    1,   0.02 FROM DUAL UNION ALL
SELECT 'INC', TO_DATE('7/18/2018','MM/DD/YYYY'),   'NEWYORK', 'US',  700000,  'RTY',     2,   0.04  FROM DUAL UNION ALL
SELECT 'INC', TO_DATE('7/24/2018','MM/DD/YYYY'),   'CHICAGO', 'US',  700000,  'CBO',     2,   0.04  FROM DUAL UNION ALL
SELECT 'INC', TO_DATE('7/25/2018','MM/DD/YYYY'),   'EUROPE',  'WG',  253235,  'EFDX',    1,   0.02  FROM DUAL ),
tmp as ( 
SELECT id.*, 
       sum(decode(status,'INC',total,'DEL',-total)) 
           over ( partition by market, country, acc, inct, vol, total) incdel 
FROM input_data id )
SELECT status, trx_date, market, country, acc, inct, vol, total
FROM   tmp 
WHERE incdel != 0;

结果：

+--------+-----------+---------+---------+--------+------+-----+-------+
| STATUS | TRX_DATE  | MARKET  | COUNTRY |  ACC   | INCT | VOL | TOTAL |
+--------+-----------+---------+---------+--------+------+-----+-------+
| INC    | 03-JUL-18 | CHICAGO | US      |  67890 | AB   |   3 |  0.06 |
| INC    | 24-JUL-18 | CHICAGO | US      | 700000 | CBO  |   2 |  0.04 |
| INC    | 06-JUL-18 | CHICAGO | US      | 700000 | CBO  |  25 |   0.5 |
| INC    | 25-JUL-18 | EUROPE  | WG      | 253235 | EFDX |   1 |  0.02 |
| INC    | 11-JUL-18 | EUROPE  | WG      | 253235 | EFDX |   1 |  0.02 |
| INC    | 18-JUL-18 | NEWYORK | US      | 700000 | RTY  |   2 |  0.04 |
+--------+-----------+---------+---------+--------+------+-----+-------+

Answer 2

有几种方法可以实现此目的。您可以执行2 CTE。发布您的查询将有所帮助！该查询不完整，您必须完成它。但是主要的想法在这里。

;with subQry1 (
    select STATUS DATE MARKET COUNTRY ACC INCT VOL, sum(??) total,
    from table
    where ...
    group by STATUS DATE MARKET COUNTRY ACC INCT VOL    
), subQry2 (
    select STATUS DATE MARKET COUNTRY ACC INCT VOL, total,
    rownumber() over(partition by MARKET, COUNTRY,ACC, INCT, VOL, TOTAL order by MARKET, COUNTRY,ACC, INCT, VOL, TOTAL) rnk
    from subQry1
) select * from subQry2 where rnk = 1;

Answer 3

听起来像'DEL'会“删除” 'INC'隐藏的记录吗？这表明NOT EXISTS可能会有所帮助。

在不知道实际查询或架构的情况下，我无法为您提供有效的查询，只是一个大概的样子：

SELECT T1.STATUS,
       T1.DATE,
       T1.MARKET,
       ...
       T1.TOTAL
       FROM ELBAT T1
       WHERE T1.STATUS = 'INC'
             AND NOT EXISTS (SELECT *
                                    FROM ELBAT T2
                                    WHERE T2.STATUS = 'DEL'
                                          AND T2.MARKET = T1.MARKET
                                          ...
                                          AND T2.TOTAL = T1.TOTAL);

按复杂查询分组

3 个答案: