Question

p3txt=np.loadtxt("data_.txt")

` 是长文本文件的示例以及它们在列中的方式。我问如何在将这些列分配给python的一行变量时如何读取文件并将这些列分开？每当我尝试将.txt转换为float类型

时，我都会收到错误

public class IdDetails
{
    public string transactionDate { get; set; }
    public string upnName { get; set; }
    public string movementTrade { get; set; }
    public string baseCurve { get; set; }
    public string cTolerance { get; set; }
    //17 more declarations below
}

是我现在正在阅读的文件

Answer 1

尝试：

skiprows=1  ->  skip the first row (because it doesn't contain numbers)
.T          ->  take transpose. numpy is [row-major](https://en.wikipedia.org/wiki/Row-_and_column-major_order) meaning that when splitting up the data it will first cut up the columns and leave the rows as whole
a, b        ->  assigning to a tuple of variables triggers the splitting up of the right-hand-side

说明：

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Python-Using Numpy，如何从.txt文件中读取数据并将数据列分配给变量

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