到目前为止,我有这个:
if (is_request_var('requestor') == 'PPA'){
$dataJson[][] = array("status" => "success","value" => $fetchValue ,"postcode" => $fetchPostCode,"params"=>"");
$notice = $dataJson;
}
我想从PHP获取(参见下文)如何安排我的PHP数组代码
jQuery191013316784294951245_1485527378760([
{
"value": "\u003cstrong\u003eNAIROBI\u003c/strong\u003e KENYATTA AVENUE, GENERAL POST OFFICE, 00100",
"postcode": "00100"
},
{
"value": "\u003cstrong\u003eNAIROBI\u003c/strong\u003e HAILE SALASSIE AVENUE, CITY SQUARE, QLD, 00200",
"postcode": "00200"
}
])
答案 0 :(得分:1)
试试这个:
$dataJson = array("value" => $fetchValue, "postcode" => $fetchPostCode);
$notice = json_encode($dataJson);
echo $notice;
返回包含值的JSON表示的字符串。