使用PHP创建JSON对象

Question

我很难使用下面的PHP代码创建以下JSON格式。请建议。

PHP代码

$postArray = array(
    "MainPage" =>  array(
        "i_date"=> "10-10-2012",
        "i_location"=>$_POST["location-text"],
        "i_summary"=>$_POST["summary-text"],
    "SubPage" => "[" array(
        "first_name"=> $_POST["first-1"],
        "last_name"=>$_POST["last-1"]
         ),
         array(
            "first_name"=>$_POST["first-2"],
        "last_name"=>$_POST["last-2"]
         ) "]"
    )
);


array_push($postArray["MainPage"]["SubPage"], 
    array(
         "first_name"=>$_POST["first-3"],
         "last_name"=>$_POST["last-3"]
    )
);

$json = json_encode( $postArray );

这是我想要实现的最终输出。

{
  "MainPage":{
    "i_date":"2014-03-20",
    "i_location":"test",
    "i_summary":"test test",
    "SubPage":[
      {
        "first_name":"first name test1",
        "last_name":"last name test1"
      },
      {
        "first_name":"first name test2",
        "last_name":"last name test2"
      },
      {
        "first_name":"first name test3",
        "last_name":"last name test3"
      }
    ]
  }
}

Answer 1

我对原始代码进行了一些更改，这些更改可以提供您想要的结果。

$postArray = array(
    'MainPage' => array(
        'i_date' => '2014-03-20',
        'i_location' => $_POST["location-text"],
        'i_summary' => $_POST["summary-text"],
        'SubPage' => array(
            array(
                'first_name' => $_POST["first-1"],
                'last_name' => $_POST["last-1"]
            ),
            array(
                'first_name' => $_POST["first-2"],
                'last_name' => $_POST["last-2"]
            )                        
        )
    )
);

$postArray['MainPage']['SubPage'][] = array(
    'first_name' => $_POST["first-3"],
    'last_name' => $_POST["last-3"]
);

$json = json_encode($postArray);