Question

我希望能够创建一个JSON对象，以便我可以像这样访问它。

education.schools.UNCC.graduation

目前，我的JSON是这样的：

var education  = {
    "schools": [
        "UNCC": {
            "graduation": 2015, 
            "city": "Charlotte, NC", 
            "major": ["CS", "Spanish"]
        },
        "UNC-CH": {
            "graduation": 2012,
            "city": "Chapel Hill, NC"
            "major": ["Sociology", "Film"]
        }
    ],
    "online": {
        "website": "Udacity",
        "courses": ["python", "java", "data science"]
    }
};

当我转到Lint my JSON时，我收到一条错误消息。我知道我可以重新格式化我的对象来访问它（如下所示），但我不想这样做。我希望能够拨打学校名称，而不是使用索引号。

education.schools[1].graduation

Answer 1

对象具有命名键。数组是成员列表。

用对象替换"schools"的值。将[]更改为{}。

Answer 2

这是你的JSON更正。您的JSON无效。

{
    "schools": [
        {
            "UNCC": {
                "graduation": "2015",
                "city": [
                    "CS",
                    "Spanish"
                ],
                "major": [
                    "CS",
                    "Spanish"
                ]
            }
        },
        {
            "UNC-CH": {
                "graduation": "2012",
                "city": [
                    "Chapel Hill",
                    "NC"
                ],
                "major": [
                    "Sociology",
                    "Film"
                ]
            }
        }
    ],
    "online": {
        "website": "Udacity",
        "courses": [
            "python",
            "java",
            "data science"
        ]
    }
}

<强>解释：

＆＃34; city＆＃34;：＆＃34; Chapel Hill，NC＆＃34; - ＆GT;这是一个包含2个值的数组＆＃34; Chapel Hill ＆＃34;和＆＃34; HC ＆＃34;，就像你对专业和课程一样。
Schools数组，你需要使用这个sintaxe来构造一个数组[{

http://adobe.github.io/Spry/samples/data_region/JSONDataSetSample.html

在不使用列表的情况下创建JSON对象

2 个答案: