我的程序找不到终端。我究竟做错了什么?

时间:2017-02-02 19:19:33

标签: python ubuntu

我正在制作一个SNAKE游戏,不久前我遇到了问题。我用了一个Windows操作系统来诅咒'而不是Linux操作系统。所以我决定继续使用Ubuntu的计算机,但现在出现了一个新的错误:

错误:

Traceback (most recent call last):
  File "/home/KMR/Documents/Snake Game .py", line 8, in <module>
    curses.initscr()
  File "/usr/lib/python3.5/curses/__init__.py", line 30, in initscr
    fd=_sys.__stdout__.fileno())
_curses.error: setupterm: could not find terminal

我的代码:

# SNAKES GAME
# Use ARROW KEYS to play, SPACE BAR for pausing/resuming and Esc Key for exiting

import curses
from curses import KEY_RIGHT, KEY_LEFT, KEY_UP, KEY_DOWN
from random import randint

curses.initscr()
win = curses.newwin(20, 60, 0, 0)
win.keypad(1)
curses.noecho()
curses.cur_set(0)
win.border(0)
win.nodelay(1)

key = KEY_RIGHT                                          # Initalizing Values
score = 5

snake = [[4,10], [4,9], [4,8]]                          # Initial snake co-ordinates
food = [10,20]                                          # First food co-ordinates                         

win.addc(food[0], food[1], '*')                             # Prints the food

while key != 27:
    win.border(0)
    win.addstr(0, 2, 'Score :' + str(score) + ' ')          # Printing 'Score' and      
    win.addstr(0, 27, ' SNAKE ')                            # 'SNAKE' strings
    win.timeout(150 - (len(snake)/5 + len(snake)/10)%120)

    prevKey = key                                           # Previous key pressed
    event = win.getch
    key = key if event == -1 else event


    if key == ord(' '):                                     # If SPACE BAR is pressed, wait for another
        key = -1                                            # one (Pause/Resume)
        while key != ord(' '):
            key = win.getch()
    key = prevKey
    continue

if key not in [KEY_LEFT, KEY_RIGHT, KEY_UP, KEY_DOWN, 27]:  # If an invalid key is pressed
    key = prevKey

    # Calculates the new coordinates of the head of the snake. NOTE: len(snake) increases.
    # This is taken care of later at [1].
    snake.insert(0, [snake[0][0] + (key == KEY_DOWN and 1) + (key == KEY_UP and -1), snake[0][1] + (key == KEY_LEFT and -1) + (key == KEY_RIGHT and 1)])

    # If snake crosses the boundaries, make it enter from the other side                
    if snake[0][0] == 0: snake[0][0] = 18
    if snake[0][1] == 0: snake[0][1] = 58
    if snake[0][0] == 19: snake[0][0] = 1
    if snake[0][1] == 59: snake[0][1] = 1

    # Exit if snake crosses the boundaries (Uncomment to enable)
    # if snake[0][0] == 0 or snake[0][0] == 19 or snake[0][1] == 0 or snake[0][1] == 59: break

    # If snake runs over itself
    def endgame():
        if snake[0]in snake[1:]: endgame()


    if snake[0] == food:
        food = []                                                                                                                           
        score += 1

1 个答案:

答案 0 :(得分:0)

import curses
import subprocess

def main():
    try:
        scr = curses.initscr()
    except _curses.error:
        subprocess.call(['lxterminal', '--command', 'python', __file__])
    else:
        run_normal_code(scr) #execute  above code in this block